The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
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Answer:
Step-by-step explanation:
Product of slope of perpendicular lines = -1
6x + 5y = 30
Write this equation in y = mx + b form
5y = -6x + 30
y = 
Slope of this line m₁ = -6/5
m₁ * m₂ = -1
m₂ = -1÷m₁ = -1 * 
& (-6 , -7)
Equation of the required line: y - y₁ = m (x - x₁)
![y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2](https://tex.z-dn.net/?f=y%20-%20%28-7%29%20%3D%20%5Cfrac%7B5%7D%7B6%7D%28x%20-%20%5B-6%5D%29%5C%5C%5C%5Cy%20%2B%207%20%3D%20%5Cfrac%7B5%7D%7B6%7Dx%20%2B%206%20%2A%5Cfrac%7B5%7D%7B6%7D%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B5%7D%7B6%7Dx%20%2B5-7%5C%5C%5C%5Cy%3D%5Cfrac%7B5%7D%7B6%7Dx-2)
Step-by-step explanation:
I don't know please mark as brilliant please
48 points gained in those 3 days.
Subtract 220 with 48, then add 96. Last step would be subtracting 220 with the amount they have now in those 3 days to find how much points the stock market gained in those 3 days.
Subtract 220-48.It‘ll be 172.
Add 172 with 96. 172+96=268.
Subtract 268 with how much points the stock market had 3 days ago. 268-220.
Sot eh stock market gained 48 points in 3 days.
