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3 years ago

B(n)=1 (-2)^n-1 What is the 4th term in the sequence

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

3 0

Answer:

The 4th term in the sequence is -8.

Step-by-step explanation:

The nth term of the sequence B is given by:

$B(n) = (-2)^{n-1}$

So the fourth term will be given by:

B when n = 4, that is, B(4).

$B(4) = (-2)^{4-1} = (-2)^{3} = -8$

The 4th term in the sequence is -8.

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In △ABC, ∠ABC = 60 degrees .

ira [324]

A given shape that is bounded by three sides and has got three internal angles is referred to as a triangle. Thus the value of PB is 8.0 units.

A given shape that is bounded by three sides and has got three internal angles is referred to as a triangle. Types of triangles include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the internal angles of any triangle is $180^{o}$ .

In the given question, point P is center of the given triangle such that <APB = <APC = <BPC = $120^{o}$ . Such that line PB bisects <ABC into two equal measures of $30^{o}$ .

Thus;

<ABP = $30^{o}$

Thus,

<ABP + <APB + <BAP = $180^{o}$

30 + 120 + <BAP = $180^{o}$

<BAP = $180^{o}$ - 150

<BAP = $30^{o}$

Apply the Sine rule to determine the value of PB, such that;

$\frac{a}{SinA}$ = $\frac{b}{SinB}$

$\frac{8}{Sin 30}$ = $\frac{PB}{Sin 30}$

BP = $\frac{8*Sin 30}{Sin 30}$

= 8

BP = 8.0

Therefore, the value of PB = 8 units.

For more clarifications on Sine rule, visit: brainly.com/question/27174058

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5 0

2 years ago

darren has 3/4 of a gallon of soil.he needs to plant 5 small plants.if he splits the soil evenly between the plants.how much soi

Natali5045456 [20]

3/4 divides by 5

3/4 x 1/5 = 3/20 of a gallon

3 0

3 years ago

Which of the following is equivalent to (16^3/2)^1/2? 6 8 12 64

Pani-rosa [81]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\left( 16^{\frac{3}{2}} \right)^{\frac{1}{2}}\implies 16^{\frac{3}{2}\cdot \frac{1}{2}}\implies 16^{\frac{3}{4}}\qquad \boxed{16=2^4}\qquad (2^4)^{\frac{3}{4}}\implies 2^{4\cdot \frac{3}{4}}
\\\\\\
2^3\implies 8$