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Harrizon [31]
3 years ago
12

Anyone know this type of equation for chemistry?

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:   3 F2  +  1 P2  ⇒ 2 PF3

Explanation:  

  Fluorine reduces from 0 ⇒ -I  and  Phosphor oxidises from 0 ⇒ + III

 <em>But usually P is in form P or P4 (white or red Phosphor)</em>

 So there need to be three F atoms receiving donated electrons from

one P atom. Then proportion F:P  =3:1

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Find the density of a substance that has a mass of 75 g and a volume of 35 mL. Don't forget your units!
Andrew [12]

Answer:

The density of a substance that has a mass of 75 g and a volume of 35 mL is 2.14 \frac{g}{mL}

Explanation:

Density is a characteristic property of a substance that relates to the amount of mass it has per unit volume. In other words, density is the property that matter, whether solid, liquid or gas, has to compress into a given space (it measures the amount of mass in a given volume of a substance). It is calculated as the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

In this case, you know:

  • mass= 75 g
  • volume= 35 mL

Replacing:

density=\frac{75 g}{35 mL}

Solving:

density=2.14\frac{g}{mL}

<u><em>The density of a substance that has a mass of 75 g and a volume of 35 mL is 2.14 </em></u>\frac{g}{mL}<u><em></em></u>

5 0
3 years ago
Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.
igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, [\text{H}^{+}] = 10^{-\text{pH}}, where [\text{H}^{+}] is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, [\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}.

[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w, where [\text{OH}^{-}] the concentration of hydroxide ions and \text{K}_w is the dissociation constant of water.

\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3} at 0.10 MPa and 25 °C. As a result, [\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}.

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B is the correct answer if I remember
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I think the answer is

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