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Vladimir [108]
3 years ago
13

457cg converted into dg

Chemistry
1 answer:
grigory [225]3 years ago
8 0
1 cg ---------- 0.1 dg
457 cg ------- ?

457 x 0.1 / 1

= 45.7 dg
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4 years ago
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Find the mass of 0.235 moles of SiO2? (NOTE: use correct significant figures!)
marta [7]

Answer: 14.1g

Explanation:

Given that,

number of moles of SiO2 = 0.235 moles

Mass in grams = Z (let unknown value be Z)

Molar mass of SiO2 = ?

To get the molar mass of SiO2, use the atomic mass

Silicon = 28g;

Oxygen = 16g

i.e Molar mass of SiO2 = 28g + (16g x 2)

= 28g + 32g

= 60g/mol

Now, apply the formula

Number of moles = Mass / molar mass

0.235 moles = Z / 60g/mol

Z = 0.235 moles x 60g/mol

Z = 14.1 g

Thus, the mass of SiO2 is 14.1 grams.

8 0
3 years ago
A cat travels 240 meters in 30 seconds, and a sprinter travels 100 meters in 9.5 seconds. Which is traveling faster, the cat or
joja [24]

Answer:

The cat

Explanation:

1) You need to find how many meters per second each thing is sprinting, so you can divide the meters by seconds for each.

\frac{240}{30} = 8 m/s\\\frac{100}{9.5} = around  10.5 m/s

2) Per second, the sprinter is able to achieve 8 meters, while the cat can do around 10.5 meters. 10.5 is greater than 8, making the cat faster than the sprinter.

4 0
2 years ago
Any help with these questions would help i'm lost
SSSSS [86.1K]

Answer:

1.  31.25 mL

2.  1.98 g/L

3.  0.45 g/mL

Explanation:

For each of the problems, you need to perform unit conversions.  You need to use the information given to you to convert to a specific unit.

1.  You need volume (mL).  You have density (g/mL) and mass (g).  Divide mass by density.  You will cancel out mL and be left with g.

(50.0 g)/(1.60 g/mL) = 31.25 mL

2.  You are given grams and liters.  You need to find density with units g/L.  This means that you have to divide grams by liters.

(0.891 g)/(0.450 L) = 1.98 g/L

3.  You have to find density again but this time with units g/mL.  Divide the given mass by the volume.

(10.0 g)/(22.0 mL) = 0.45 g/mL

5 0
3 years ago
A 1.87 L aqueous solution of KOH contains 155 g of KOH . The solution has a density of 1.29 g/mL . Calculate the molarity ( M ),
Semenov [28]

Answer:        

[KOH] : 1.47 M

[KOH] : 1.22 m

[KOH]: 6.42 % mass percent.      

Explanation:

First of all we must determine the volume of solution. We have to work with the density

Density = mass / volume

1.29 g/ml = mass / 1870 ml

1.29 g/ml . 1870 ml = 2412.3

Now we must convert the mass to moles

155g / 56.1 g/ mol = 2.76 moles

Now we can calculate molarity

2.76 mol / 1.87 L = 1.47 M

To calculate molality we have to find out the mass of solvent

mass solute + mass solvent = mass solution

155 g + mass solvent = 2412.3 g

2412.3g - 155g = 2257.3g

We have to convert the 2257.3 g to kg

2257.3 g = 2.25 kg

molality = 2.76 moles / 2.25 kg = 1.22 m

To find out the % mass percentation, we have to calculate the mass of solute in 100 g of solution.

In 2412.3 g of solution we have 155 g of KOH

In 100 g of solution, we would have (100 . 155) / 2412.3 = 6.42 %mass percent.

7 0
3 years ago
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