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3 years ago

A 2.00L mixture of helium, nitrogen, and neon has a total pressure of 815 mmHg at a

Chemistry

1 answer:

Olin [163]3 years ago

4 0

Answer: The partial pressure of neon in the mixture is 263 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_{He}+p_{N_2}+p_{Ne}$

Given : $p_{total}$ =total pressure of gases = 815 mm Hg

$p_{He}$ = partial pressure of helium = 201 mm Hg

$p_{N_2}$ = partial pressure of nitrogen = 351 mm Hg

$p_{Ne}$ = partial pressure of Neon = ?

putting in the values we get:

$815mm Hg=201 mm Hg+351 mm Hg+p_{Ne}$

$p_{Ne}=263mmHg$

The partial pressure of neon in the mixture is 263 mm Hg

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3 years ago

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gregori [183]

Answer:

v = 16.49 m/s

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Given that,

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3 years ago

How many significant figures are in 4.800x10-3?

seraphim [82]

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2 years ago

PLEASE HELP!! GIVING BRAINLIEST

RSB [31]

Answer:

The answer is "0.00172172603".

Explanation:

Given:

$Mass (M) = 1.60 \times 10^{-3} \ g\\\\Density (D) = 9.293 \times 10^{-1} \ \frac{g}{cm^3}\\\\Volume (V) = ?$

Formula:

$\to \bold{V = \frac{M}{D}}$

$= \frac{1.60 \times 10^{-3}}{9.293 \times 10^{-1}} \\\\ = \frac{1.60 \times 10^{1}}{9.293 \times 10^{3}} \\\\ = \frac{1.60 \times 10}{9.293 \times 1000} \\\\ = \frac{1.60 }{9.293 \times 100} \\\\ = \frac{1.60 }{929.3 } \\\\= 0.00172172603$

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3 years ago