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Nikitich [7]
3 years ago
15

A 2.00L mixture of helium, nitrogen, and neon has a total pressure of 815 mmHg at a

Chemistry
1 answer:
Olin [163]3 years ago
4 0

Answer: The partial pressure of neon in the mixture is 263 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{He}+p_{N_2}+p_{Ne}

Given : p_{total} =total pressure of gases = 815 mm Hg

p_{He} = partial pressure of helium = 201 mm Hg

p_{N_2} = partial pressure of nitrogen = 351 mm Hg

p_{Ne} = partial pressure of Neon = ?

putting in the values we get:

815mm Hg=201 mm Hg+351 mm Hg+p_{Ne}  

p_{Ne}=263mmHg

The partial pressure of neon in the mixture is 263 mm Hg

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Darin skateboarded to the north at 4 m/s. In 5 seconds, he sped up to 7 m/s. What was his acceleration?
Julli [10]
To solve this problem we can use following equation.

v =u + at

Where v is the final velocity (m/s), u is the initial velocity (m/s), a is the acceleration (m/s²) and t is the time taken (s).

v = 7 m/s
u = 4 m/s
a = ?
t = 5 s

By applying the equation, we can get
    7 m/s = 4 m/s + a x 5 s
    3 m/s = a x 5 s
          a = 0.6 m/s²

Hence, the acceleration is 0.6 m/s² towards north.

Answer is "C".
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Which unit measures mass?
Artyom0805 [142]

kilograms are the unit that measures mass

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Which of the following are not single-displacement reactions?
Goshia [24]

Answer:

\boxed{\text{B and C }}

Explanation:

In a single-displacement reaction, one element exchanges partners with another element in a compound.

\textbf{A. } \rm Fe + 2HCl \longrightarrow FeCl_2 + H_2

This is a single-displacement reaction, because the element Fe exchanges partners with H in HCl.

\textbf{B. } \rm KOH + HNO_3 \longrightarrow H_2O + KNO_3

This is not a single-displacement reaction, because it is a reaction between two compounds.

This is a double displacement reaction in which the K⁺ and H⁺ cations change partners with the anions.

\textbf{C. } \rm Na_2S + 2HCl \longrightarrow 2NaCl + H_2S

This is not a single-displacement reaction. It is another double displacement reaction, in which the Na⁺ and H⁺ cations change partners with the anions.

\textbf{D. } \rm Ca + 2HOH \longrightarrow Ca(OH)_2 + H_2

This is a single-displacement reaction, because the element Ca exchanges partners with H in H₂O.

\boxed{\textbf{B and C }} are not single-displacement reactions.

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The primary anthropogenic source of atmospheric carbon dioxide (co2 ) is
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Burning of oil,gases and coal are the antropogenic source of co2 
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In the laboratory a student combines 26.2 mL of a 0.234 M chromium(III) acetate solution with 10.7 mL of a 0.461 M chromium(III)
Natalka [10]

<u>Answer:</u> The molarity of Cr^{3+} ions in the solution is 0.299 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For chromium (III) acetate:</u>

Molarity of chromium (III) acetate solution = 0.234 M

Volume of solution = 26.2 mL

Putting values in equation 1, we get:

0.234=\frac{\text{Moles of chromium (III) acetate}\times 1000}{26.2}\\\\\text{Moles of chromium (III) acetate}=\frac{0.234\times 26.2}{1000}=0.00613mol

1 mole of chromium (III) acetate (Cr(CH_3COO)_3) produces 1 mole of chromium (Cr^{3+}) ions and 3 moles of acetate (CH_3COO^-) ions

Moles of Cr^{3+}\text{ ions}=(1\times 0.00613)=0.00613moles

  • <u>For chromium (III) nitrate:</u>

Molarity of chromium (III) nitrate solution = 0.461 M

Volume of solution = 10.7 mL

Putting values in equation 1, we get:

0.461=\frac{\text{Moles of chromium (III) nitrate}\times 1000}{10.7}\\\\\text{Moles of chromium (III) nitrate}=\frac{0.461\times 10.7}{1000}=0.00493mol

1 mole of chromium (III) nitrate (Cr(NO_3)_3) produces 1 mole of chromium (Cr^{3+}) ions and 3 moles of nitrate (NO_3^-) ions

Moles of Cr^{3+}\text{ ions}=(1\times 0.00493)=0.00493moles

  • <u>For chromium cation:</u>

Total moles of chromium cations = [0.00613 + 0.00493] = 0.01106 moles

Total volume of solution = [26.2 + 10.7] = 36.9 mL

Putting values in equation 1, we get:

\text{Molarity of }Cr^{3+}\text{ cations}=\frac{0.01106\times 1000}{36.9}\\\\\text{Molarity of }Cr^{3+}\text{ cations}=0.299M/tex]Hence, the molarity of [tex]Cr^{3+} ions in the solution is 0.299 M

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