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ikadub [295]
3 years ago
13

if a genetic error occurred, resulting in each liver cell in a person having only 1,000 insulin receptors, what specific effect

would this have on the liver cells?
Biology
2 answers:
lianna [129]3 years ago
8 0
<span>If a person had only 1000 insulin receptors in each liver cell instead of the usual 90,000 or more, the person would not be able to take in or absorb the normal amount of insulin, store glucose as efficiently, or regulate blood sugar levels as efficiently.</span>
andrew11 [14]3 years ago
4 0

When the levels of glucose in the blood elevate, the beta cells in the pancreas discharge insulin that encourages uptake of glucose for storage and metabolism. This hormone is recognized by the insulin receptors found in the surface of the cell.  

If an individual is having 1000 insulin receptors, in each cell of the liver in spite of exhibiting the usual 90000 or more, then the individual would not possess the tendency to consume or absorb the usual amount of insulin, monitor the levels of sugar as effectively, or store glucose as effectively.  


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Lubov Fominskaja [6]

why does our nose get stuffy when we have a cold

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Due to dilation of blood vessels in the sinuses of the nose

Explanation:

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We get stuffed due to the body's homeostasis, a drive to internally control and balance the outside environment.

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6 0
3 years ago
10
lina2011 [118]

Explanation:

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5 0
2 years ago
During what cycle are sugars produced in the chloroplast
iren2701 [21]

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3 0
3 years ago
In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of allele a is 0.2. what is the
Allushta [10]
The Hardy-Weinberg equation is as follows:
( {p + q})^{2}  = 1
{p}^{2}  +2pq +   {q}^{2}  = 1
Where:
(convert all % to decimals)

p= homozygous dominant
q= homozygous recessive
pq= heterozygous

While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.

Using the 1st equation, we can solve for the other dominant/recessive frequency:

1-0.2=0.8

Meaning that:

p= 0.8 & q=0.2

If the heterozygouz frequency is 2pq, then it becomes a simple "plug & chug" sort of approach.

2(0.8)(0.2)= 2(0.16)= 0.32

So, the heterozygous frequency would be:
0.32

Hope this helps!
8 0
3 years ago
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yanalaym [24]

Answer:

A.

Explanation:

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7 0
3 years ago
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