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3 years ago

Pls helppp! thank you so much

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

7 0

Cge I believe hope this helps

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Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.

leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

$12x-5y+14=0 \\ 12x-5y-14=0$

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1$

$\Rightarrow 12h-5k-1=\pm 13$

$\Rightarrow 12h-5k=\pm 14$

$\Rightarrow 12h-5k=14,\ 12h-5k=-14$

$\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0$

$\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0$

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0

3 years ago

Please help me with this question

WITCHER [35]

Answer:

you can't cheat in an online school math test =_=

Step-by-step explanation:

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3 years ago

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The question is...................

Norma-Jean [14]

B is dilated by a factor of 5

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3 years ago

Disregarding sales tax, how much will you save when

docker41 [41]

Answer:

$2.40

Step-by-step explanation:

$12.00÷100=0.12x20=2.4

hope this helps, have a good day.

5 0

2 years ago

Find a solution to the following system of equations. –2x + 5y = 8 2x + 2y = 6

aksik [14]

-2x + 5y = 8
2x + 2y = 6
----------------add
7y = 14
y = 14/7
y = 2

2x + 2y = 6
2x + 2(2) = 6
2x + 4 = 6
2x = 6 - 4
2x = 2
x = 2/2
x = 1

solution is (1,2)

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3 years ago

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