Answer:
Possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.
Step-by-step explanation:
Let the length of the silk fiber = x yards.
Let the number of silk fibres = a.
It is given that the silk fibers between 3 to 10 yards are combined to form a silk thread of 300 yards.
So, we get the equation,
, where 
i.e.
, 
So, the possible values of 'a' are 3, 4, 5, 6 an 10.
Thus, the possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.
150 = 5 classes
1 class = 30
Look at the vertical line on the graph and find five
Place a dot there
Look at the horizontal line and look to the left to find -7
Place a dot there
Now, just get a ruler and draw a line connecting the two dots
Answer:
-1
Step-by-step explanation:
4x-1=-4
-4+3=-1
A translation by 11 units to the left and 3 units up