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vladimir2022 [97]
3 years ago
14

Parallelogram ABCD is dilated to form parallelogram EFGH. Side BC is proportional to side CD. Which corresponding side is propor

tional to segment FG? Type the answer in the box below. (5 points)

Mathematics
2 answers:
NARA [144]3 years ago
7 0

Answer with explanation:

Pre-Image=Parallelogram ABCD

⇒When ║gm ABCD is Dilated , as Preimage is larger, Dilation factor is <1,we get Image parallelogram EFGH.

Image=Parallelogram EFGH

⇒It is also given that, side BC is proportional to side CD.

→BC ∝ CD

→BC=k ×CD

\frac{BC}{CD}=k

Now, the Original Parallelogram ABCD and Dilated Parallelogram EFGH will be similar,that is their corresponding sides will be proportional and corresponding interior angles will be equal.

⇒∠A=∠E, ∠B=∠F,∠C=∠G,∠D=∠H.

\Rightarrow \frac{AB}{EF}=\frac{BC}{FG}=\frac{CD}{GH}=\frac{AD}{EH}\\\\\Rightarrow\frac{BC}{FG}=\frac{CD}{GH}\\\\\Rightarrow\frac{BC}{CD}=\frac{FG}{GH}=k

⇒Corresponding side  proportional to segment F G is G H.

AlexFokin [52]3 years ago
6 0

The side that is proportional is GH

Hope this helps!

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I need help on my homework
soldi70 [24.7K]

Answer:

\displaystyle m\angle AED=32.5^\circ

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

\displaystyle m\angle AED=\frac{AD-BC}{2}

\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}

\displaystyle m\angle AED=32.5^\circ

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En un experimento de laboratorio se mezcla dextrosa y agua en varios recipientes, con la condición de que la concentración de de
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4give me I need the points T_T

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(05.03)(picture included)Sue has to cut her grandma's grass this weekend and wants to know exactly how much area she will be cut
kifflom [539]

Answer:

Solution given:

BD=35ft

AC=43ft

AB=8ft

EF=33-8=25ft

AE=26ft

Now

area of right angled triangle ∆AEF

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area of parallel trapezoid=½AB(BD+AC)

=½*8(35+43)=312ft²

<u>So</u>

<u>Area</u><u> </u><u>of</u><u> </u><u>polygon</u><u> </u><u>:</u><u> </u><u>3</u><u>1</u><u>2</u><u>.</u><u>5</u><u>+</u><u>3</u><u>1</u><u>2</u><u>=</u><u>6</u><u>2</u><u>4</u><u>.</u><u>5</u><u>f</u><u>t</u><u>²</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>

3 0
3 years ago
Read 2 more answers
three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.
jasenka [17]
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
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3rd Integer
=x+4
=91+4
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ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)
7 0
3 years ago
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