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ladessa [460]
3 years ago
14

Which of the following is a factor of x2 − 8x + 15?

Mathematics
2 answers:
IrinaVladis [17]3 years ago
5 0

Answer:

x+5

Step-by-step explanation:

edge

brilliants [131]3 years ago
3 0

Answer:

(x−3)(x−5)

Step-by-step explanation:

Let's factor x2−8x+15

x2−8x+15

The middle number is -8 and the last number is 15.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -8

Multiply together to get 15

Can you think of the two numbers?

Try -3 and -5:

-3+-5 = -8

-3*-5 = 15

Fill in the blanks in

(x+_)(x+_)

with -3 and -5 to get...

(x-3)(x-5)

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drek231 [11]

Answer:

a:c = 35:24

a:c = 20:27

a:c = 35:22

a:c = 28:27

Step-by-step explanation:

a:b = 7:3

Using cross products

3a = 7b

Divide by 7

3a/7 = b

Now we want

8b = 5c

Substitute in 3a/7 for b

8 (3a/7) = 5c

24/7a = 5c

Multiply by 7

24/7a *7 = 5*7c

24a = 35c

Divide by c

24 a/c = 35

Divide by 24

a/c = 35/24

a:c = 35:24

a:b = 4:9

Using cross products

9a = 4b

Divide by 4

9a/4 = b

Now we want

3b = 5c

Substitute in 9a/4 for b

3 (9a/4) = 5c

27/4a = 5c

Multiply by 4

27/4a *4 = 5*4c

27a = 20c

Divide by c

27 a/c = 20

Divide by 27

a/c = 20/27

a:c = 20:27

b:c = 5:11

Using cross products

11b = 5c

Divide by 11

b = 5c/11

Now we want

2a = 7b

Substitute in 5c/11 for b

2a = 7(5c/11)

2a = 35c/11

Multiply by 11

2a*11 = 35c

22a = 35c

Divide by c

22 a/c = 35

Divide by 22

a/c = 35/22

a:c = 35:22

b:c = 14:3

Using cross products

3b = 14c

Divide by 3

b = 14c/3

Now we want

9a = 2b

Substitute in 14c/3 for b

9a = 2(14c/3)

9a = 28c/3

Multiply by 3

9a*3 = 28c

27a = 28c

Divide by c

27 a/c = 28

Divide by 27

a/c = 28/27

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7 0
3 years ago
The table shows a pattern of exponents. Powers of 5 Value 5 cubed 125 5 squared 25 5 Superscript 1 5 5 Superscript 0 1 5 Supersc
dimaraw [331]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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Encuentra la ecuacion de la parabola con vertice en el origen y foco en las cordenadas 0,1en su forma ordinaria y general
marusya05 [52]

Answer:

x^{2}=4y

y=\frac{1}{4}x^{2}

Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

(x-h)^{2}=4p(y-k) (1)  

Donde:

  • (h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
  • (h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

(x-0)^{2}=4*1(y-0)

x^{2}=4y (2)

 

Forma general  

La forma general de una parábola esta dada por la siquiente ecuación

y=ax^{2}+bx+c

Reordenando la ecuación (2) tenemos:

y=\frac{1}{4}x^{2}

Espero esto te haya ayudado!

5 0
3 years ago
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ludmilkaskok [199]

Answer:

B.

Step-by-step explanation:

Domain is the x-coordinate and the range is the y-coordinate.

B. Domain: {7}

Range: {-4, -2, 1, 4, 6}

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2 years ago
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kolbaska11 [484]

Answer:

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