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fredd [130]
3 years ago
13

(a) दिइएको चतुभुर्जको क्षेत्रफल पत्ता

Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0

Answer:

मैं वास्तव में अच्छा हूं

मैं धाराप्रवाह हिंदी बोलता हूं

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How do you write 1.0x10^-3 in standard form?
riadik2000 [5.3K]

Answer: 1/1000

Step-by-step explanation:

1 * 10^-3 = 1 * 1/10^3 = 1/1000

4 0
3 years ago
Read 2 more answers
Can someone solve these please using the formula AB | a - b |<br><br> And can you show work
Lana71 [14]

Answer: 1) AC = 13

The formua does not actually apply to all of the problems.

Step-by-step explanation:

1) The absolute value of -8 is added to the absolute value of 5. 8+5=13

2) Subtract the length of the EF from EG to get the length of FG 21 -6 = 15

3) Take what's given and create an equation to solve. 4x + 15 +39 =110. 4x = 110 - (15+39).

4x =110-54. 4x =56. x=56/4. x=14

4) Create another equation. You have two segments that add up to the length of EG, given =23

EF+FG=EG

(2x-12)+(3x-15)=23

5x - 27 = 23

5x= 23+27 5x =50. x = 10

Substitute 10 for x

EF=2(10) -12 EF=8

FG=3(10)-15. FG=15

EF+FG =EG.

8 + 15 = 23

5) 2/5 of 25 is 10 So EF is 10. Subtract from 25 to get FG

FG = 15

I hope this helps you.

4 0
3 years ago
How do i find the scale factor?
AnnyKZ [126]

Answer:

1:3.7

Step-by-step explanation:

1331/27

Then cube root

3.66666666667

Round

3.7

(i believe)

8 0
3 years ago
part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.​
andreev551 [17]

Answer:  \bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c²  , <em>where "c" is the hypotenuse</em>

5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}

Note: (15)² + (3√11)² = hypotenuse²   →   hypotenuse = 18

6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}

Note: 8² + 15² = hypotenuse²   →   hypotenuse = 17

7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}

Note: hypotenuse not needed for tan

8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}

Note: 2² + 6² = hypotenuse²   →   hypotenuse = 2√10

8 0
3 years ago
Q3. Kylie sits two maths test. She scores 19/25 in the first one, and 16/20 in the second one.
Rina8888 [55]
She done better at the 2nd test because she only got 4 wrong but on the first test she got 6 wrong.
7 0
3 years ago
Read 2 more answers
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