Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
Answer:
m = -2
y-intercept = 4
Step-by-step explanation:
m = y2-y1/x2-x1
so
m = -2-4/3-0
=-2
y=mx+b
Substitute the coordinates into the equation to find b
4=-2(0)+b
4=b
so y intercept is 4
y=-2x+4
Absolute value only removes the negative signs. Just multiply the numerator and the denominator
i did the awnser is 173,668.18 there you goStep-by-step explanation:
Answer:
a)ab=-6×+4=-24
b)a÷d=-6÷-2=3
c)2bd=2×+4×-2=-16
Step-by-step explanation:
Put the values according to the question
Hope it help you
