Hello from MrBillDoesMath!
Answer:
33
Discussion:
2 tens = 2 * 10 = 20
13 ones = 13 * 1 13
=> 2 tens + 13 ones = 20 + 13 = 33
Thank you,
MrB
Answer:

Step-by-step explanation:
Given


Required:
Calculate the angle between u and v
The angle
is calculated as thus:

For a vector


becomes




For a vector


So;






So:






Take arccos of both sides





<em></em>
<em> (approximated)</em>
Answer:
x=80
Step-by-step explanation:
im going to assume this is perimeter.
50+50=100
260-100=160
160÷2=80
4 quarts is equal to 1 gallon
Just multiply 26 by 4 and get 104
Since the ratio of girls and boys must be the same in each team, and all the competitors must be involved, it means that each team's ratio of boys : girls must be equal to the total ratio of Boys : Girls = 36 :27= 4 / 3.
Now 4 / 3, the most simplified version of 36 / 27, happens by dividing the numerator & demoninator by 9 (the greatest number it can divide by). So the greatest number will be 9 teams, each of 4 Boys & 3 Girls