A = 1 + 5^3-x, Isolate the variable by dividing each side by factors that don't contain the variable.
The first step is to find the slope of the given line by putting its equation in the form y = mx + b.
9y = x - 18
Dividing both sides by 9, gives:
y = (x/9) - 2
The slope of the given line is therefore 1/9.
Let the slope of the perpendicular line be m.
The product of the two slopes must equal -1 for the lines to be perpendicular.

Therefore m = -9.
At this stage the equation of the required line is y = -9x + b.
Now we need to find the value of b.
Plugging the given values of a point on the line (6, -1) into the equation gives:
-1 = -54 + b; from which b = 53.
The required equation for the line is:
f(x) = -9x + 53.
Answer:
x=4
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3(x+2)=2(x+5)
(3)(x)+(3)(2)=(2)(x)+(2)(5)(Distribute)
3x+6=2x+10
Step 2: Subtract 2x from both sides.
3x+6−2x=2x+10−2x
x+6=10
Step 3: Subtract 6 from both sides.
x+6−6=10−6
x=4
thus answers.hooe it's right
Answer:
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Step-by-step explanation: