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alina1380 [7]
3 years ago
11

Karina is creating a new passcode for her phone. Her

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0

Answer:

The answer is: 10^5=100'000

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Giving brainliest and max rating.
Yanka [14]

Given:

The cost of each carnival ticket is $5.

To find:

The equation, table of values and graph for the given problem.

Solution:

Let x be the number of tickets and y be the total money spent on tickets.

Cost of one ticket = $5

Cost of x tickets = $5x

So, total cost is

y=5x

The required equation is y=5x.

At x=1,

y=5(1)

y=5

At x=2,

y=5(2)

y=10

At x=3,

y=5(3)

y=15

The required table of values is

x       y

1        5

2      10

3      15

So, the required table of values is table A.

From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.

So, the required graph is graph B.

Since the required answers are y=5x, table A, graph B, therefore the correct option is B.

8 0
2 years ago
The expression 2y+3y2−5y+y2simplifies to 4y2−3y <br> true or false
Mumz [18]

Answer:

False?

Step-by-step explanation:

I'm pretty sure it's false because wouldn't it simplify to 5y? Sorry if I'm wrong. :)

8 0
3 years ago
Find an equation of a line that comes close to the points listed in the table.
sergey [27]
y=x+2\\x=6\to y=6+2=8\\x=10\to y=10+2=12\\x=12\to y=12+2=14\\x=16\to y=16+2=18\\x=18\to y=18+2=20\\-----------------------\\y=x+3\\x=6\to y=6+3=9\\x=10\to y=10+3=13\\x=12\to y=12+3=15\\x=16\to y=16+3=19\\x=18\to y=18+3=21\\-----------------------\\Answer:y=x+1.5
3 0
3 years ago
SOMEONE PLEASE HELP ILL MARK U BRAINLIST
Lemur [1.5K]

Answer:

The value of X is 1

Step-by-step explanation:

Trust me i did this already.

4 0
2 years ago
Read 2 more answers
A sample of size 20 from a normal distribution has sample mean 3.5 and sample variance 14.75. Find 90% confidence intervals for
aleksley [76]

Answer:

Variance =9.2983, 27.6927

Standard deviation = 3.0493, 5.2624

Step-by-step explanation:

n = 20

S = 14.75

X² = chisquare

N-1 = degree of freedom

Alpha = 0.1

Alpha/2 = 0.1/2 = 0.05

1-0.1/2 = 0.95

Using statistics table

X² 19,0.05 = 30.14

X² 19, 0.95 = 10.12

A. 19(14.75)/30.14 , 19(14 75)/10.12

= 9.2983, 27.6927 for the variance of the population

B. Standard deviation = square root of variance

= √9.2983, √27.6927

= 3.0493, 5.2624

Please use attachment for better understanding

5 0
3 years ago
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