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kvasek [131]
3 years ago
10

Tracey is at the store and buys 3 shirts for $15 each and a 3 pairs of pants for $25 each. She also has a coupon for $12 off her

total. Write an expression that could be written to determine the answer.
Mathematics
2 answers:
sineoko [7]3 years ago
6 0

Answer:

45+135+12

Step-by-step explanation:

SOVA2 [1]3 years ago
4 0
Answer:

(3x15+3x25)-12
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The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum h
BabaBlast [244]

Answer:

The maximum height of the projectile is 90 ft

Step-by-step explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

We have this as;

y = -16t^2 + 64t + 26

That will be;

y = a(x-h)^2 + k

y = -16(x-2)^2 + 90

where the vertex of the equation is;

(-h,k)

K

in this case is 90 and thus, that is the maximum height of the projectile

8 0
3 years ago
Write 0.00034 as a multiple of a power of 10.
adelina 88 [10]
3.4*10^-4
hope this helps!!
7 0
3 years ago
Read 2 more answers
Simplify the expression-3(b-7)
oee [108]
-3(b - 7)

Multiply -3 into the parenthesis.

= -3b + 21.
8 0
3 years ago
Read 2 more answers
( x + 3 )( y + 2 ) = xy - 5<br> ( x + 2 )( y - 3 ) = xy
Paraphin [41]

Answer:

xy+2x+3y+6=xy-5 .............(1)

xy-3x+2y-6=xy.....,.,(2)

2x+3y=-11

-4x+2y=6

first equation multiply by 2

(2)*(2x+3y)=-11

4x+6y=-22

-4x+2y=6

8y=-16 y=(-2),,,,, x=(-2,5)

4 0
3 years ago
What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
Travka [436]
The standard equation of a circle is

(x-h)^2 + (y-k)^2 = r^2

where the center is at point (h,k)

From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be

r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241

Thus, the equation of the circle is

(x-2)^{2} + (y+5)^{2} =241
4 0
2 years ago
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