Answer:
The two numbers are <em>16</em> and <em>26</em>.
Step-by-step explanation:
We can solve this question using 2 simultaneous equations based on the given information from the question.
Let number 1 = x
Let number 2 = y
xy = 416 -> ( 1 )
x + y = 42 -> ( 2 )
We can use either substitution or elimination to solve simultaneous equations. For this question, we will use substitution as it is the easier and shorter option.
Make y the subject in ( 2 ):
x + y = 42 -> ( 2 )
y = 42 - x -> ( 3 )
Substitute ( 3 ) into ( 1 ):
xy = 416 -> ( 1 )
x ( 42 - x ) = 416
42x - x^2 = 416
-x^2 + 42x - 416 = 0
- [ x^2 - 42x + 416 ] = 0
- [ x^2 - 16x - 26x + 416 ] = 0
- [ x ( x - 16 ) - 26 ( x - 16 ) ] = 0
- ( x - 16 ) ( x - 26 ) = 0
x = 16 -> ( 4 ) , x = 26 -> ( 5 )
Substitute ( 4 ) into ( 3 ):
y = 42 - x -> ( 3 )
y = 42 - ( 16 )
y = 26
Substitute ( 5 ) into ( 3 ):
y = 42 - x -> ( 3 )
y = 42 - ( 26 )
y = 16
Therefore:
x = 16 , y = 26
x = 26 , y = 16
The two numbers are 16 and 26.
<h3>
Answer: y = 9</h3>
====================================================
Explanation:
Locate 12 on the horizontal x axis number line.
Then move straight up until reaching the parabola.
Afterward, move to the left to arrive at y = 9 on the vertical y axis.
We predict the y value will be y = 9 for the input of x = 12.
Refer to the diagram below to see what's going on.
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
<span>6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player. </span>
<span>So the bleachers are 9/2 x 6 ft = 27 ft. </span>
<span>For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216. </span>
<span>So the stage will have dimensions 216 times larger than 1.75" by 3". </span>
<span>That would be 31ft 6ins x 54ft. </span>
Answer:
8.60
Step-by-step explanation:
8.602
since 2 is below 5 it cant change the 0
so
0 will stay 0
