If I understand the question correctly, you can have the same amount of change be two different percentages by having 4 quarters and 100 pennies.
Each quarter is 25%
Each penny is 1%
(am i explaining this right)
In this expression you would have to use the PEMDAS method. First divide, so (5 divided by 8) + (2 divided by 9).
The answer you would get is: (0.625) + (0.222)
The final answer is: 0.847
Answer:
Step-by-step explanation:
<u>Given:</u>
- AB = 192 cm
- AC : CB = 1 : 3
- CD = BC/12
- The distance between midpoints of AD and CB = x
<u>Find the length of AC and CB:</u>
- AC + CB = AB
- AC + 3AC = 192
- 4AC = 192
- AC = 192/4
- AC = 48 cm
<u>Find CB:</u>
<u>Find the length of CD:</u>
- CD = BC/12 = 144/12 = 12 cm
<u>Find the length of AD:</u>
- AD = AC - CD = 48 - 12 = 36 cm
<u>Find the midpoint of AD:</u>
<u>Find the midpoint of CB:</u>
- m(CB) = AC + 1/2CB = 48 + 144/2 = 48 + 82 = 130 cm
<u>Find the distance between the midpoints:</u>
Answer: C.
There are 215 total students in the band.
There are 27 seniors in the band.
The probability is found by dividing the number of seniors in the band by the TOTAL number of students in the band.
P(S|B) = 27/215 = 0.1255813953
You have to round off the answer too the nearest tenth.
P(S|B) = 0.13
Answer:
Step-by-step explanation:
