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3 years ago

9

HELP PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ i will be very happy if u do. FIRST PERSON TO GET IT CORRECT GETS BRAINLIEST

1 answer:

Vsevolod [243]3 years ago

8 0

Answer:

Step-by-step explanation:

x -12 > 0

x > 12

if x > 12 x-12

if x = 12 0

if x < 12 12-x

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joey's mom baked two dozen cookies . that night, there were only 14 cookies left. what percentage of the cookies were eaten?

Aleksandr [31]

Answer:

41.67 % ( to 2 dec. places )

Step-by-step explanation:

Since 2 dozen cookies were baked, that is 24 and 14 were left.

Then 10 were eaten.

Calculate the percentage eaten as

percentage = $\frac{numbereaten}{original}$ × 100%

percentage eaten = $\frac{10}{24}$ × 100% ≈41.67%

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3 years ago

What's the word form and the number form

KengaRu [80]

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Number form: 600,000+80,000+10

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4 years ago

Rewrite this fraction as a decimal 15/4

NISA [10]

Answer:

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Step-by-step explanation:

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4 years ago

Read 2 more answers

israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa

agasfer [191]

Lets solve our radical equation $\sqrt{x+6}-4=x$ step by step.

Step 1 add 4 to both sides of the equation:

$\sqrt{x+6} -4+4=x +4$

$\sqrt{x} +6=x+4$

Step 2 square both sides of the equation:

$\sqrt{x+6} =x+4$

$\sqrt{x+6}^2 =(x+4)^2$

$x+6=(x+4)^2$

Step 3 expand the binomial in the right hand side:

$x+6=x^2+8x+16$

Step 4 simplify the expression:

$0=x^2+8x-x+16-6$

$x^2+7x+10=0$

Step 5 factor the expression:

$(x+2)(x+5)=0$

Step 6 solve for each factor:

$x+2=0$ or $x+5=0$

$x=-2$ or $x=-5$

Now we are going to check both solutions in the original equation to prove if they are valid:

For $x=-2$

$\sqrt{x+6}-4=x$

$\sqrt{-2+6}-4=-2$

$\sqrt{4}-4=-2$

$2-4=-2$

$-2=-2$

The solution $x=2$ is a valid solution of the rational equation $\sqrt{x+6}-4=x$ .

For $x=-5$

$\sqrt{x+6}-4=x$

$\sqrt{-5+6}-4=-5$

$\sqrt{1}-4=-5$

$1-4=-5$

$-3\neq -5$

Since -3 is not equal to -5, the solution $x=-5$ is not a valid solution of the rational equation $\sqrt{x+6}-4=x$ ; therefore, $x=-5$ is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

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3 years ago

Find the circumference of the circle

Ann [662]

C = 8 x pi
C = 8 x 3.14
C = 25.12

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3 years ago