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Viefleur [7K]
3 years ago
11

Reflect the point in the y-axis

Mathematics
2 answers:
SVEN [57.7K]3 years ago
4 0

Answer:

A(-1,3),B(2,-2),C(4,5),D(-2,-5)

levacccp [35]3 years ago
3 0

Answer:

A(-1,3) ;B(2,-2); C(4,5); D(-2,-5)

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How do I Draw the graph of the function f(x) = 3⌊x⌋ for the domain −1 ≤ x < 2
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Go to the website symbolab.com 
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8 0
3 years ago
The graph of y=-3x+ 2 is:
Alexeev081 [22]

Answer:

A

Step-by-step explanation:

This is a linear function whose slope is -3 and whose y-intercept is (0, 2).  Answer A is correct.

5 0
3 years ago
Kanna Kamui eats a bowl of rice weighing 50 oz total. If the bowl weighs 22 oz, then what was the weight of rice Kanna ate.
Alex Ar [27]

Answer:

28

Step-by-step explanation:

Take the weight of the bowl out of the rice

8 0
3 years ago
Read 2 more answers
Express 18 as a product of its factors?​
Dimas [21]

Answer:

18= 2 x 3 x 3

Step-by-step explanation:

Basically, we branch out 18 into its prime factors. So, the prime factorization of 18 is 18= 2 × 3 × 3. A factor tree is not unique for a given number. Instead of expressing 18 as 2 × 9, we can express 18 as 3 × 6.

7 0
2 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
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