Answer:
your answer would to your question is d
Answer:
The length of the rectangle (l) = 3 feet
The width of the rectangle (W) = 10 feet
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the width of the rectangle = (x+1) feet</em>
<em>Given that the length of the rectangle = ( x-6) feet</em>
<em>The area of the rectangle = 30 square feet</em>
<u><em>Step(ii):-</em></u>
We know that the area of the rectangle
= length ×width
30 = ( x+1)(x-6)
30 = x² - 6x + x -6
⇒ x² - 5 x - 6 = 30
⇒ x² - 5 x - 6 - 30 =0
⇒ x² - 5 x - 36 =0
x² - 9 x +4x - 36 =0
x (x-9) +4 ( x-9) =0
( x+4 ) ( x-9) =0
( x+4 ) =0 and ( x-9) =0
x =-4 and x =9
<u><em>Step(iii):-</em></u>
we have to choose x =9
The length of the rectangle (l) = x-6 = 9-6 =3
The width of the rectangle (W) = x+1 = 9 +1 = 10
<u><em>Final answer:-</em></u>
The length of the rectangle (l) = 3 feet
The width of the rectangle (W) = 10 feet
Answer:
23 thousandths. <em><u>=</u></em><em><u> </u></em> 23 ÷ 10^3
9+4 × (6÷3) <em><u>></u></em> (9+4×6) ÷ 3
5 tens + 2 hundredths. <em><u><</u></em> 50.20
810.6 ÷ 10. <em><u>=</u></em> 8.106 × 10
Answer:
The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.
<em />
Step-by-step explanation:
<em>The question is incomplete:</em>
<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>
We can model this as a binomial random variable, with p=0.57 and n=14.

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:



