Whats the square root of 45

ANSWER THIS FOR ME PLEASEEE !!

maw [93]

Answer:

Its is the second bubble! Hope this is right!

Step-by-step explanation

They have 100 squares, 75 are shaded, Its a fraction 75 over 100!

6 0

4 years ago

1. (5 points) At 6pm, ghost A is 5 kilometers due west of ghost B. Ghost A is flying west

zaharov [31]

Answer:

The distance between the ghost changes at 10 pm approximately at a rate of 24.981 kilometers per hour.

Step-by-step explanation:

At first we assume that north and east directions both represent positive quantities. Let suppose that $\vec r_{A,o} = (0\,km,0\,km)$ and $\vec r_{B,o} = (5\,km, 0\,km)$ . If both ghosts moves at constant velocity such that $\vec v_{A} = \left(-15\,\frac{km}{h}, 0\,\frac{km}{h} \right)$ and $\vec v_{B} = \left(0\,\frac{km}{h},20\,\frac{km}{h} \right)$ , then the final positions of both ghosts are, respectively:

Ghost A

$\vec r_{A} = \vec r_{A,o}+t\cdot \vec v_{A}$ (Eq. 1)

Ghost B

$\vec r_{B} = \vec r_{B,o}+t\cdot \vec v_{B}$ (Eq. 2)

Where $t$ is the time, measured in hours.

Then, the equations of motion of each ghost are, respectively:

Ghost A

$\vec r_{A} = (0\,km,0\,km)+t\cdot \left(-15\,\frac{km}{h}, 0\,\frac{km}{h} \right)$

$\vec r_{A} = \left(-15\cdot t, 0)\,\,\,\left[km \right]$

Ghost B

$\vec r_{B} = (5\,km, 0\,km)+t\cdot \left(0\,\frac{km}{h}, 20\,\frac{km}{h} \right)$

$\vec r_{B} = (5, 20\cdot t)\,\,\,\left[km\right]$

Then, the distance between both ghosts is:

$\vec r_{B/A} = (5,20\cdot t)-(-15\cdot t, 0)\,\,\,[km]$

$\vec r_{B/A} =(5+15\cdot t, 20\cdot t)\,\,\,[km]$ (Eq. 3)

The magnitude of the relative is represented by the following Pythagorean identity:

$r^{2}_{B/A} = (5+15\cdot t)^{2}+(20\cdot t)^{2}$

Then, we find the rate of change of the relative distance ( $\dot r_{B/A}$ ), measured in kilometers per hour, by implicit differentiation:

$2\cdot r_{B/A}\cdot \dot r_{B/A} = 2\cdot (5+15\cdot t)\cdot 15+2\cdot (20\cdot t)\cdot 20$

$r_{B/A}\cdot \dot r_{B/A} = 15\cdot (5+15\cdot t)+20\cdot (20\cdot t)$

$\dot r_{B/A} = \frac{75+625\cdot t}{r_{B/A}}$

$\dot r_{B/A} = \frac{75+625\cdot t}{\sqrt{(5+15\cdot t)^{2}+(20\cdot t)^{2}}}$ (Eq. 4)

If we know that $t = 4\,h$ , then the rate of change of the relative distance at 10 PM is:

$\dot r_{B/A} = \frac{75+625\cdot (4)}{\sqrt{[5+15\cdot (4)]^{2}+[20\cdot (4)]^{2}}}$

$\dot r_{B/A} \approx 24.981\,\frac{km}{h}$

The distance between the ghost changes at 10 pm approximately at a rate of 24.981 kilometers per hour.

4 0

3 years ago

Answer the question plz and be the brainliest

snow_tiger [21]

Step-by-step explanation:

Maryam scores in paper 1 65% × 120

= 65/100 × 120

= 78 marks of full scores 120 marks

scores in paper 2 80% × 80

= 80/100 × 80

= 64 marks of full scores 80 marks

4 0

3 years ago

Jessie has been training for a half-marathon. Jesse trains on a track where each lap is 1/4 of a mile. If Jesse ran 3 1/7 miles,

NISA [10]

Answer:

14.2

Step-by-step explanation:

4 0

3 years ago

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The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is

liraira [26]

we know that

The LCD is the LCM (least common multiple) of all the denominators.

we have

$1/3, 3/4, 5/32, 8/9$

$3=3^{1} \\ 4=2^{2} \\ 32=2^{5} \\ 9=3^{2}$

$LCM=2^{5} *3^{2} \\ LCM=32*9\\ LCM=288$

So

The LCM of $3, 4, 32, 9$ is $288$ ,

which is the multiple of the highest power of prime factors from all of the given numbers

therefore

the answer is

$288$

8 0

3 years ago

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