Required area of shaded portion
= Area of square ABCD - 4 × area of one quadrant

Draw a rectangle with diagonal 5 in. Inside this rect. are 2 acute triangles of hypotenuse 5. Note that 3^2 + 4^2 = 5^2; thus the width of the rect. is 3 and the length is 4, with the result that the hypo. is sqrt(3^2+4^2), as expected.
The answer would be (A) <span>(x − 4)^2 + (y − 4)^2 = 16
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Answer:
Q6. D
Q8. A
Step-by-step explanation:
Q6. In 40 trials, he flipped '2 heads and 1 tail' 16 times.
For 2 heads, probability= 16/40= 4/10
For 120 trials, number of times= 4/10 × 120= 48
Q8.

Answer is A because the inequality shows that x is equal or greater than 8 so the dot at 8 has to be coloured.
Note that we do not change the inequality sign unless we are dividing the whole thing by -1.