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ss7ja [257]
2 years ago
12

SHOW WORK NEED HELP ASSP

Mathematics
2 answers:
12345 [234]2 years ago
5 0

Answer:

Student B is incorrect

Step-by-step explanation:

They added terms with variables of different powers.

ser-zykov [4K]2 years ago
4 0
It is not our problem do it by your self
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Hi
Alona [7]
You’re absolutely amazing and I really appreciate that you’re trying to help others! And if you need anything yourself please feel free to ask :)
5 0
3 years ago
Determine the amplitude (A), period (P), and phase shift (PS) of the function f(x)= 3sin(x-4)+9
Tpy6a [65]
ANSWER

D.
A=3,P=2\pi,PS=(4,9)

EXPLANATION

The given function is

f(x) = 3 \sin(x - 4) + 9

Comparing to the general form of a trigonometric sine function,

f(x) = A \sin(Bx-C)+D

A=3
The amplitude is absolute value of A

|A| = |3| = 3

B=1

The period is given by

p = \frac{2\pi}{ B}

p = \frac{2\pi}{ 1} = 2\pi

C=4

is a shift to the right of 4 units.

and

D=9

is an upward shift of 9 units

Therefore the phase shift is (4,9).

The correct answer is D
6 0
3 years ago
Victoria ran 3/4 a mile in 1/3 of an hour. If she continues at this rate, How far will she run in 1 hour
weqwewe [10]

Answer:

2 ¼ miles

Step-by-step explanation:

we can use a ratio

miles:hrs

¾:⅓

x3 x3

9/4:1

2¼:1

3 0
3 years ago
Professor Goodheart has two exams, exam 1 and exam 2. The exam 1 weights 40% and the exam 2 weights 60% of the final grades. Put
garri49 [273]

Answer:

Imperfect substitutes

explanation:

The choices above are not perfect substitutes, meaning they can not be perfectly or directly replace the other. Imperfect substitutes are close substitutes but not perfect substitutes. Unlike perfect substitutes, imperfect substitutes satisfies same utility but has different characteristics and therefore not entirely substitutable. For example, while one may want to have the 40 marks too, he'd rather have 60 marks even if the criteria for a 60 mark score was increasingly hard.

8 0
3 years ago
Convert 0.83 into a fraction.​
Anastasy [175]

0.83 * 100 = 83, so 0.83 = 83/100.

But in case you meant the slightly more interesting repeating decimal, 0.8333...:

Let <em>x</em> denote this number. Then

10<em>x</em> = 8.333...

100<em>x</em> = 83.333...

==>  100<em>x</em> - 10<em>x</em> = 83.333... - 8.333...

==>  90<em>x</em> = 83 - 8 = 75

==>  <em>x</em> = 75/90 = 5/6

4 0
3 years ago
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