I need help please. I don't get how to do systems of linear equations!!!!!!!

1 answer:

4 0

The soluition set is (-3,5) and a normal ordered pair reads (x,y). So that means 5 = [_]x-10
-Add 10 to both sides
15 = [_]x
-And we know the value of x so lets sub that in.
15 = [_](-3)
-And now we divide by -3
-5 = [_]

Next we have 3x-[_]y=-19
-Lets start this buy substituting values of x and y into the equation again.
3(-3)-[_](5)=-19
-Simplify
-9 - [_](5) = -19
-Move the (-9) by adding 9 to both sides
-[_](5) = -10
-divide by 5 = -2
-(1)[_] = -2
[_] = 2

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\begin{array}{llll}
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\qquad variation
\end{array}\\\\
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