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Arte-miy333 [17]
3 years ago
15

Guys need help asap plz ill give brainliest to first person that is correct. you put the answer for 1c and 2 below. I just need

the answers plz help. AND DONT ANSWER FOR POINTS OR I WILL REPORT YOU. please i beg you i have lost hundreds of points because of people who do that.
Question 1: Consider: y = x squared - 6x + 4
a) Write the equation of the axis of symmetry.
b) Find the coordinates of the vertex. Is it a maximum or minimum?
c) Graph the function.

Question 2) Solve by graphing: x squared + 4x+6 = 0

Question 3) Describe how the graph of each function is related to the graph of f(x) = x squared.
a) g(x) = x squared +3
b) g(x) = -x squared - 1

guys i really need this. for number 1c and 2, can you take a picture of the graph you made if you did. I appreciate all help but try to do as much as you can. plz plz plz plz.
Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

Step-by-step explanation:

Vertex = 3,-5

line of symmetry = x = 3

Its a minimum

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Answer:

26 units

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Using the formula above,

distance between (-10, 3) and (0, 27)

=  \sqrt{ {( - 10 - 0)}^{2}  +  {(3 - 27)}^{2} }

=  \sqrt{ {10}^{2}  + ( - 24) {}^{2} }

=  \sqrt{100 + 576}

=  \sqrt{676}

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3 years ago
1. If x=3-√3,<br> prove that x²<br> +36<br> x²<br> = x²
valentina_108 [34]

Answer:

we get x^2=12-6\sqrt{3}

Step-by-step explanation:

We are given: x=3-\sqrt{3}

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Solving:

x=3-\sqrt{3} \\Taking \ square \ on \ both \ sides\\x^2=(3-\sqrt{3})^2\\

We know that (a-b)^2= a^2-2ab+b^2

Using formula and simplifying

x^2=(3)^2-2(3)(\sqrt{3})+(\sqrt{3})^2\\x^2=9-6\sqrt{3} +3\\x^2=12-6\sqrt{3} \\

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I need help with properties of rhombus, rectangles and squares ​
Montano1993 [528]

Answer:

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The same-side angles at each base are supplementary, so ...

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Because the trapezoid is isosceles, 60° also the measure of ∠C.

The angle sum theorem tells you ...

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3 years ago
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