1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Savatey [412]
3 years ago
9

A car that retails for $14,999 has a sticker on the windshield that says, "$429/mo for 48 months." What interest rate is this ca

r financed at?
Mathematics
2 answers:
kkurt [141]3 years ago
4 0
14,999(1+.o825)^4= 20,595. $429x48 months= 20,592
Interest rate 8 1/4%

Check 20592/14999= 1.37289
Log(1.37289)/ log(1.0825)= 3.99 years
Vlad1618 [11]3 years ago
3 0

Answer:

r=8.2%

Step-by-step explanation:

A car that retails for $14,999 has a sticker on the windshield that says, "$429/mo for 48 months." What interest rate is this car financed at?

from compound interest formula

A=P(1+r%)^n

The parameters are

A=amount, 429*48=20592

n=48 months, 4 years

r%=?

P=14999

20592=14999(1+r%)^4....dividing both sides by 14999

1.372=(1+r%)^4

find the fourth root of both sides

1+r%=1.082

r%=0.082

r=8.2%

the interest fate on the car will be the above.

You might be interested in
Someone please help me. I will give you hella points I need this answer to like graduate type
PtichkaEL [24]

Answer:

  • $9 and $7

Step-by-step explanation:

<u>The first equation:</u>

  • x + 2y = 23

<u>The second equation:</u>

  • 2x + 3y = 39

<u>Convert to slope-intercept form:</u>

  • x + 2y = 23 ⇒ 2y = -x + 23 ⇒ y = -1/2x + 11.5
  • 2x + 3y = 39 ⇒ 3y = -2x + 39 ⇒ y = -2/3x + 13

<em>The graph is attached</em>

<u>Intersection point is (9, 7)</u>

  • Adult tickets cost $9
  • Child tickets cost $7

8 0
3 years ago
Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following.
bonufazy [111]
4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2

5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3

6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
4 0
3 years ago
How to set up the equation and solve for x and y variables
aleksklad [387]

y = mx + b

I mean, thats the formula? :/

8 0
3 years ago
The drama club is selling tickets to its play. An adult ticket costs $15 and a student ticket costs $11. The auditorium will sea
spin [16.1K]

Answer:

83 adult tickets and 217 student tickets.

Step-by-step explanation:

Let number of adult tickets sold = x

Given that total number of tickets = 300

So, number of student tickets = 300 - x

Cost of adult ticket = $15

Cost of student ticket = $11

Total collection from adult tickets = $15x

Total collection from student tickets =  (300-x)\times 11 = 3300-11x

Given that overall collection = $3630

15x+(3300-11x) = 3630\\\Rightarrow 15x-11x=3630-3300\\\Rightarrow 4x = 330\\\Rightarrow   x = 82.5

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.

Now , collection = $3632

4 0
3 years ago
Evaluate 3x^3 - 5y^2 x=5 y=2
Sliva [168]

Answer:

355

Step-by-step explanation:

3x^{3}-5y^{2}=3*5³-5*2²

3*5³-5*2²=3*125-5*4

3*125-5*4=375-20

375-20=355

6 0
3 years ago
Other questions:
  • Which expression is equivalent to (73)−2?
    5·1 answer
  • Write an exponential equation in the form y = abx whose graph passes through points (−3, 24) and (−2, 12). y = 3x y = 3(0.5)x y
    9·1 answer
  • 1. Name a pair of vertical angles.
    11·1 answer
  • Find the value of 373 using the identity (x − y)3 = x3 − 3x2y + 3xy2 − y3. Show all work.
    14·1 answer
  • Another doctor suggest that for women, there are two researched formulas to find a maximum heart rate m in terms of age a m=220
    11·1 answer
  • Translate (3, – 4) down 3 units.<br> Then reflect the result over the y-axis.
    5·1 answer
  • An airplane flying with the wind takes 2 hours to travel a distance
    10·1 answer
  • HELP PLS I CAnt DO THIS
    13·1 answer
  • PLs help
    12·1 answer
  • Solve for x in the following problem: 9 = 3/5x
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!