2 years ago

Helppppppppppppppp please ty <3 !

Mathematics

1 answer:

ad-work [718]2 years ago

8 0

Answer:

31,547 I used subtraction. I just subtracted 54,927-23,380.

Step-by-step explanation:

54,927

-23,380

------------

31,547

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Let $\mathbf u\in\mathbb R^2$ , where

$\mathbf u=(u_1,u_2)$

and let $k\in\mathbb R$ be any real constant.

Given this definition of scalar multiplication, we can see right away that there is no identity element $e$ such that

$e\mathbf u=\mathbf u$

because

$e\mathbf u=e(u_1,u_2)=(eu_1,0)\neq(u_1,u_2)=\mathbf u$