Answer:
Each student ticket costs $8.33
Each adult ticket costs $15.34
Step-by-step explanation:
At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?
s = cost of each student ticket
a = cost of adult ticket
Our system of equations:
4s + 2a = 64
3s + 3a = 71
-3(4s + 2a = 64) ==> -12s - 6a = -192
2(3s + 3a = 71) ==> 6s + 6a = 142
-12s - 6a = -192
6s + 6a = 142
-6s = -50
/-6 /-6
s = $8.33 (the cost of each student ticket)
Now, let's find the cost of each adult ticket:
4s + 2a = 64
4(8.33) + 2a = 64
33.32 + 2a = 64
-33.32 -33.32
2a = 30.68
/2 /2
a = 15.34 (the cost of each adult ticket)
(x, y) ==> (8.33, 15.34)
Check your answer:
4s + 2a = 64
4(8.33) + 2(15.34) = 64
33.32 + 30.68 = 64
64 = 64
This statement is true
Hope this helps!
Answer:
A is the only possible correct answer since the center of that shape is x =-1
Answer:
![8^6](https://tex.z-dn.net/?f=8%5E6)
Step-by-step explanation:
Powers are defined as the number of times you multiply a number by itself. For example, 2 to the 3rd power is 2 multiplied by itself 3 times. 2 * 2 * 2 = 8. You also know that if you multiply two powers of the same base, you add the exponent, and if you raise a power to a different power, you multiply the exponents.
e.g:
![2^2\cdot2^2=2^{2+2}=2^4\\(2^2)^3=2^{2\cdot3}=2^6](https://tex.z-dn.net/?f=2%5E2%5Ccdot2%5E2%3D2%5E%7B2%2B2%7D%3D2%5E4%5C%5C%282%5E2%29%5E3%3D2%5E%7B2%5Ccdot3%7D%3D2%5E6)
Now, we are asking to use grouping to write 2 to the power 18 as a power of 8. We know 2 to the power 8 is 2 to the power 3, so we have the following equation:
![2^{18}=(2^3)^x](https://tex.z-dn.net/?f=2%5E%7B18%7D%3D%282%5E3%29%5Ex)
We know this is now 2 to the power 3x = 2 the power 18, and therefore x = 6, because 3 times 6 is equal to 18. Now, we can just simplify 2 to the third as 8 and we now have:
![8^6](https://tex.z-dn.net/?f=8%5E6)
Answer:
4 + 60 + 300 + NaN + 70000 + 600000 + 1000000 + NaN + 900000000
Remark
Let the pigs = p
Let the chickens = c
Givens
30 heads is another way of saying that there were 30 creatures in the barnyard. In addition each chicken has 2 legs and each pig has 4
c + p = 30
2C + 4P = 100 (2) Divide (2) by 2
C + 2P = 50 (3) Subtract (1) from (3)
<u>C + P = 30</u>
P = 20
So there were 20 pigs.