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Licemer1 [7]
3 years ago
6

Solving right triangles

Mathematics
1 answer:
ratelena [41]3 years ago
3 0
All you need is use sin cos tan for doing this
sin (angle)= O/H
cos (angle)= A/H
tan (angle)= O/A
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For <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%204x%2B1" id="TexFormula1" title="f(x) = 4x+1" alt="f(x) = 4x+1" align="abs
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\bf \begin{cases} f(x)=4x+1\\ g(x)=x^2-5\\[-0.5em] \hrulefill\\ (f\circ g)(4)=f(~~g(4)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ g(4)=(4)^2-5\implies g(4)=16-5\implies \boxed{g(4)=11} \\\\\\ f(~~g(4)~~)\implies f(11)\implies f(11)=4(11)+1\implies \blacktriangleright f(11)=45\blacktriangleleft

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3 years ago
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LUCKY_DIMON [66]

Answer:

it should be 0.7

Step-by-step explanation:

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3 years ago
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Thank you guys fir the help
Lubov Fominskaja [6]
The correct answer to that would be b
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3 years ago
The length of a rectangle is four times its width.
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I think it would be 324 divided by 4 = 81 in.
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