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Mashutka [201]
3 years ago
7

Please show your work

Mathematics
2 answers:
Artemon [7]3 years ago
8 0

the answer is b, -8

Explanation:

Iteru [2.4K]3 years ago
8 0
Ok so we know from the question that these letters have values, so let’s rewrite the fraction with the right numbers

-4+4 x 3 8
———— = —— Divide 8 by -1 which equals -8
-4 + 3 -1


The answer must be B
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11111nata11111 [884]

Since the diagonals of a parallelogram bisect each other, it follows that:

WM=\frac{1}{2}(WY)WM\text{ =}\frac{1}{2}\times8=4

The correct answer is 4cm

7 0
2 years ago
A right rectangular prism has edges measuring 3/4 inch, 1 inch, and 1/4 inch. How many cubes with side lengths of 1/4 would be n
MAVERICK [17]

Answer: 8

Step-by-step explanation:

Ask yourself how many can go into each number? 1/4=1.

1=4.

3/4=3.

4 0
3 years ago
Read 2 more answers
What is the slope-intercept form of 6x - y - 2 = 0
nordsb [41]

Answer:

y=6x-2

Step-by-step explanation:

6x-y-2-6x=0-6x

-y-2=-6x

-y-2+2=-6x+2

-y=-6x+2

-y/-1=-6x/-1+2/-1

y=6x-2

4 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
vichka [17]

Answer:

equation 1: 60*<em>(x-3.5)</em>=22.5*<em>x</em>     to solve for x

equation 2: <em>x</em>+<em>(x-3.5)</em>    to solve for hours

[answer at the bottom if you need it]

Step-by-step explanation:

Let's think about it in terms of x.

Suppose <em>x </em>hrs is the time it takes to get BACK. So the time to get there is <em>(x-3.5)</em> hrs.

60mph can be written as 60mi/hr. 22.5mph can be written as 22.5mi/hr.

You know that the distance there and back should be the same because Dan is going to the lake and back. To find distance of each trip, you have to multiply speed and time.

Distance TO: 60mi/hr * <em>(x-3.5)</em>hr

Distance BACK: 22.5mi/hr * <em>x</em> hr

The hr units cancel out to leave mi (miles, unit for distance)

Since the distance there and back are the same, you can set the distances equal to each other and solve for x.

60*<em>(x-3.5)</em>=22.5*<em>x</em>

That's not it though. Solving for x only gives you what x is, which is the time it takes to get back. The total time that the trip takes is<em> </em><em>x</em>+<em>(x-3.5)</em>, which is the time it takes to get there and come back from the lake.

Answer:

x= 5.6

x+(x-3.5) = 5.6+(5.6-3.5) = 5.6+2.1 =<em> </em><em><u>7.7 hours total</u></em>

<em><u></u></em>

<em><u></u></em>

Hope this was helpful!

5 0
4 years ago
Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)
dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

<h3>How to find the mass?</h3>

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = \int_a^b \delta\left|r^{\prime}(t)\right| d t

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}

Further simplifying;

\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}

Now, use integration to find the mass of the wire;

       \begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0
2 years ago
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