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QveST [7]
2 years ago
12

among 210 student 85 price in English 125 price in Nepali and 25 failed in both subject find the number of students who passed i

n both subjects and illustrate the result obtained when diagram​
Mathematics
1 answer:
notka56 [123]2 years ago
5 0

Answer:

210=85+125-x+25

x= 235-210

x=25 failled in both

Step-by-step explanation:

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1 poin
mars1129 [50]

Answer:

The building is 187.5 feet tall.

Step-by-step explanation:

A nearby person is 6 feet tall, and casts a shadow that is 8 feet long.

This means that the relation between the real height and the shadow is given by:

\frac{6}{8} = \frac{3}{4}

A tall building casts a shadow that is 250 feet long. How tall is the building?*

The real height is three fourths of the shadow. So

\frac{3}{4}*250 = 187.5

The building is 187.5 feet tall.

8 0
3 years ago
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kolbaska11 [484]
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3 years ago
You deleted 18 of your Facebook friends which was 2/3 of your friends.How many Facebook friends do you have left?
Schach [20]
6

18 divided by 3 is 6
3 0
3 years ago
Read 2 more answers
A man who is 6 feet tall casts a shadow that is 11 feet long. At the same time, a tree casts a shadow that is 33 feet long. What
Rina8888 [55]

Set up a proportion:

6 feet over 11 feet long equals x feet over 33 feet long

6/11 = x/33

198 = 11x

x = 18

The height of the tree is 18 feet tall

8 0
3 years ago
Read 2 more answers
Plzzzz help and I'll give you brainliest ​
sdas [7]

Step-by-step explanation:

Left hand side:

4 [sin⁶ θ + cos⁶ θ]

Rearrange:

4 [(sin² θ)³ + (cos² θ)³]

Factor the sum of cubes:

4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]

Pythagorean identity:

4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]

Complete the square:

4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]

4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]

Pythagorean identity:

4 [1 − 3 sin² θ cos² θ]

Rearrange:

4 − 12 sin² θ cos² θ

4 − 3 (2 sin θ cos θ)²

Double angle formula:

4 − 3 (sin (2θ))²

4 − 3 sin² (2θ)

Finally, apply Pythagorean identity and simplify:

4 − 3 (1 − cos² (2θ))

4 − 3 + 3 cos² (2θ)

1 + 3 cos² (2θ)

3 0
3 years ago
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