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QveST [7]
3 years ago
12

among 210 student 85 price in English 125 price in Nepali and 25 failed in both subject find the number of students who passed i

n both subjects and illustrate the result obtained when diagram​
Mathematics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

210=85+125-x+25

x= 235-210

x=25 failled in both

Step-by-step explanation:

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I don’t get this at all, can someone please help
JulsSmile [24]

Answer:

m = 44

Step-by-step explanation:

USe the pythagoream thyroem a^2 + b^2 = m^2. so 10^2 + m = 12^2

or 100 + m = 144. subtract 100 from both sides, you get m = 44

6 0
3 years ago
HELP ME ON THIS MATH PLEEASEEEEEEEEE
Bess [88]
C. 51* I am pretty sure is it
3 0
3 years ago
Read 2 more answers
Solve the quadratic equation 6x2 + 1 = 5x. Show your work.
Artyom0805 [142]

Answer:

<h2>Factors = (3x - 1) (2x - 1)</h2><h2>values :- x = 1/3 , 1/2</h2>

Step-by-step explanation:

= > 6x^2 + 1 = 5x

• Bring it in the standard form,

= > 6x^2 - 5x + 1 = 0

= > 6x^2 - (3 + 2)x + 1 = 0

= > 6x^2 - 3x - 2x + 1 = 0

• Take out common

= > 3x (2x - 1) - 1 (2x - 1) = 0

= > (3x - 1) (2x - 1) = 0...factors

= > x = 1/3 and 1/2... values of x

<h2>Hope it helps you!! </h2>

7 0
2 years ago
Which of the equations below represents a line perpendicular to the x-axis?
Allushta [10]

Answer:

Option B

Step-by-step explanation:

we know that

A line perpendicular to the x-axis is a line parallel to the y-axis

so

the equation of the line is of the form x=(+/-)a

The slope of the line is undefined

where

a is a real number

therefore

x=6 is a line perpendicular to the x-axis

5 0
3 years ago
Read 2 more answers
Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1,3).
Nataliya [291]

Answer:

Step-by-step explanation:

for two lines to be parallel they MUST have the same slope but have different Y intercepts ( Y axis crossing values)

parallel lines will never intersect each other

first I use a graphing calcuator to solve the problem

I like to use y intercept form better, but you don't have use it

I will try to solve it directly without going through the y intercept equation

x + 5y = 10    in y intercept form y = mx + b is

5y = -x + 10     divide both sides by 5

y = -x/5 + 10/5    

y = -x/5 + 2

Now I need to find a parallel line that passes through the x =1 and y = 3 point recall this line will have the same slope =     m = -1/5

and a different Y axis crossing point 'b' that we don't know

y = -x/5 + b      y = 3 when x = 1 so slove for 'b'

3 = -1/5 + b

3 = -0.2 + b    add -0.2 to both sides

3.2 = b

y = -x/5 + 3.2     this is answer in y intercept form

                          if you multiply both sides by 5

5y = -x + 16        add x to both sides

x + 5y = 16         answer in standard form

THE EASIER WAY TO SOLVE THE PROBLEM IS ......

x + 5y = 10      find a line parallel that passes through x  = 1,  y = 3  

x + 5y = Z       Z is an unknown value  plug in x and y and solve for Z

1 + 5(3) = Z

Z = 16              so the parallel line in standard form is

x + 5y = 16    

same as before,  my y intercept method was correct, but not  worth the effort

       

6 0
3 years ago
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