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SCORPION-xisa [38]
3 years ago
14

Imagine running a 64-bit system on a 32-bit system, where we simulate a single 64- bit memory location (register) using two atom

ic 32-bit memory locations (registers). A write operation is implemented by simply writing the first 32-bits of the simulated 64-bit register in the first real register, then the second 32-bits in the second real register. A read, similarly, reads the first half from the first register, then the second half from the second register, and returns the concatenation. What is the strongest property that this 64-bit register satisfies: safe, regular, or atomic
Computers and Technology
1 answer:
Brut [27]3 years ago
5 0

Answer:

It's not possible to ensure memory access occurs indivisibly when it has to broken into multiple operations. Unfortunately, the fact that your application is running on a 64-bit kernel does not change the equation any - it is actually running in a compatibility layer and has none of the benefits of x64

Explanation:

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