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lubasha [3.4K]
3 years ago
7

Write a function called simulate_several_key_strikes. It should take one argument: an integer specifying the number of key strik

es to simulate. It should return a string containing that many characters, each one obtained from simulating a key strike by the monkey.
Computers and Technology
1 answer:
Furkat [3]3 years ago
7 0

Answer:

The solution code is written in Python 3

  1. import random
  2. import string
  3. def simulate_several_key_strikes(l):
  4.    char_set = string.ascii_lowercase
  5.    return ''.join(random.choice(char_set) for i in range(l))
  6. print (simulate_several_key_strikes(10))

Explanation:

The program is aimed to generate random characters and the number of characters generated is dependent on user input. Hence, we will need to import the random module (Line 1). We also import string module so that we can make use of its associated method to generate English letters (Line 2)

Next, we create the function simulate_several_key_strikes that takes one single parameter, l, as input. Within the function body, we use ascii_lowercase method to generate the lowercase letter set and assign it to char_set variable (Line 5). We use random.choice method to randomly pick one of the letter in char_set and join it with an empty string (Line 6). Please note there is a for-loop that will repeatedly generate l-number of character and eventually return it as output.

We test the function by passing 10 as input parameter and we shall get a sample output as follows:

xuiczuskoj

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Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex:
ArbitrLikvidat [17]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 

 System.out.print("Enter a number: ");

 int userVal = input.nextInt();

 

 String aString;

 if(userVal < 0)

     aString = "negative";

 else

     aString = "non-negative";

     

 System.out.println(aString);

}

}

Explanation:

Ask the user to enter a number and set it to userVal

Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"

Print the string

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Rejected Options :

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Answer:

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Read 2 more answers
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Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

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//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

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Answer:

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Explanation:

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