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marishachu [46]
3 years ago
15

PLEASE HELP LMALNEBDKE 5TH GRADE MATH

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0

Answer:

the third one

Step-by-step explanation:

frutty [35]3 years ago
6 0

Answer:

the third answer is correct

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In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF.
gulaghasi [49]

Answer:

2.7 square inch

Step-by-step explanation:

\triangle BAC \sim \triangle EDF... (Given) \\

\therefore By area of similar triangle theorem:

\frac{A(\triangle BAC)}{A(\triangle EDF)} = \frac{BC^2}{EF^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{3^2}{2^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{9}{4} \\\\\therefore A(\triangle EDF) = \frac{4\times 6}{9} \\\\\therefore A(\triangle EDF) = \frac{24}{9} \\\\\therefore A(\triangle EDF) = 2.6667\\\\\huge \purple {\boxed {\therefore A(\triangle EDF) = 2.7\: in^2}}

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4 years ago
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Answer:

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Step-by-step explanation:

because that to solve the two unkown number you must have two equations of it in order to solve it

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Step-by-step explanation:

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