Question

Please help!

Answer 1

Answer: A. 0.032

Step-by-step explanation:

Answer 2

Answer:

$\text{A. 0.032}$

Step-by-step explanation:

Let $\sigma_p$ be the standard error of the distribution of sample proportions.

Formula:

$\sigma_p=\sqrt{\frac{P(1-P)}{n}}$, where $P$ is the population parameter and $n$ is sample size.

What we're given:

• $P$ of 0.1
• $n$ of 90

Substituting given values, we get:

$\sigma_p=\sqrt{\frac{0.1(1-0.1}{90}},\\\sigma_p=\sqrt{\frac{0.1\cdot 0.9}{90}},\\\sigma_p=\sqrt{0.001}\approx\boxed{\text{A. 0.032}}$