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rodikova [14]
2 years ago
5

3/8 x (1 - 1/3) (don’t answer the equation write the equation in word form)

Mathematics
1 answer:
stellarik [79]2 years ago
8 0

Answer:

three-eighths multiplied by the difference of one and one-third.

Step-by-step explanation:

Convert equation to words

3/8 = three-eighths

x = multiplied

1 - 1/3 = difference of one and 1/3

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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4.6w - 3 + 6.4x - 1.9y <br> What are the terms and coefficients?
Soloha48 [4]

For the algebraic expression 4.6w - 3 + 6.4x - 1.9y, the terms are 4.6w, - 3, 6.4x, and - 1.9y, and the coefficients are 4.6, 6.4, and -1.9 respectively.

Given: To find terms and coefficients in 4.6w - 3 + 6.4x - 1.9y

What are algebraic expressions?

Algebraic expressions are sequences or combinations of characters containing letters, numbers, variables, symbols, operands, etc.

They help in making a big problem short and to make a relationship between different parts of the problem.

What are the terms?

In algebraic expressions, terms are individual components involved in forming the algebraic expression except for the operators.

What are coefficients?

In algebraic expressions, coefficients are the numbers of letters that are associated with the variables.

Let's solve the given problem:

Given algebraic expression: 4.6w - 3 + 6.4x - 1.9y

Therefore the terms in the algebraic expression are: 4.6w, - 3, 6.4x, and - 1.9y

and the coefficients are: 4.6, 6.4, and -1.9 as w, x, and y are the variables or unknowns of the given algebraic expression.

Hence for the algebraic expression 4.6w - 3 + 6.4x - 1.9y, the terms are 4.6w, - 3, 6.4x, and - 1.9y, and the coefficients are 4.6, 6.4, and -1.9 respectively.

Know more about "terms and coefficients" here: brainly.com/question/13867708

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8 0
1 year ago
write the restrictions that should be imposed on the variable for each of the following function. then find, explicitly, the dom
matrenka [14]

By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1  b) p≤1/2  c) s>-1.

I found the complete question on Chegg, here is the full question:

Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1)  b) g(p)=√(1-2p)  c) m(s)= (s^2+4s+4)/√(s+1)

Ans. We know that a number is not divisible by zero and number inside a square root can not be negative. In both the cases the outcome will be imaginary.

a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.

b) For this case the value inside square root can’t be negative. So, p can’t be greater than 1/2 the domain is p≤1/2.

c) For this case also the value inside square root can’t be negative and the denominator value can’t be zero. So, s can’t equal or less than -1 and domain is s>-1.

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2 years ago
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777dan777 [17]

Answer:

Step-by-step explanation:

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