The Cena can take 7 courses
We have given that the karate charges $35 for the first course and $22.50 for each course after that. Our total is $170.
<h3>What is the condition we can write here?</h3>
for solving this linear equation
First, subtract 35 from both sides.
isolate x so divide both sides by 22.50.
Therefore we get x = 6
Remember to add the additional class, so x is actually 7.
So,the Cena can take 7 courses.
To learn more about the linear equation visit:
brainly.com/question/1549055
We can factorise this to get (x-9)(x-9). To find the value, each bracket needs to equal 0, so the value would be x=9
D.) 9,987,000 becomes 9.987 x 10^6
14 will be your whole number and your fraction would be 63/100, so the entire thing as a mixed number is 14 63/100
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
