Question

What type of solutions does the quadratic equation, 8v2 + 8 = -11v, have?

Answer 1

Answer:

Complex roots

Step-by-step explanation:

Given

$8v^2 + 8 = -11v$

Required

The type of solution

Rewrite as:

$8v^2 +11v+ 8 = 0$

To determine the type of solution, we simply calculate the discriminant (D)

$D = b^2 - 4ac$

Where

$a = 8;\ \ \ b =11\ \ \ c = 8$

So, we have:

$D = 11^2 - 4 * 8 * 8$

$D = 121 - 256$

$D = -135$

The above value implies that:

$D$

When $D$, the solution of the equation is: complex roots