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3 years ago

#10 am I correct Can you explain If I'm incorrect then what is the answer

Mathematics

1 answer:

Bad White [126]3 years ago

6 0

Yes, u are correct, hope this helped

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What is the factorization of the polynomial below<br>-x^2 - 15x - 56

Andrej [43]

Answer:

Step-by-step explanation:

This is more easily understood if you take out a common factor of -1

-1(x^2 + 15x + 56)

7*8 = 56

7 + 8 = 56

-1 (x +8)(x+7)

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2 years ago

Annie borrowed $354 from her parents to buy a tablet. She plans to pay the money back in 12 equal payments.

Ber [7]

$354 divided by 12 equal payments equals $29.50 a payment

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3 years ago

(7a-1)^2 please help me quickly

Sav [38]

Answer:

14a-2

Step-by-step explanation:

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2 years ago

Please help really quick what is the area

SashulF [63]

60 in^2 because bxh=a and 15x4=60

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3 years ago

An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th

Natasha2012 [34]

Answer:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the 9% confidence interval is given by:

$8.8104 \leq \mu \leq 11.1248$

We can calculate the mean with the following:

$\bar X = \frac{8.8104 +11.1248}{2}= 9.9676$

And we can find the margin of error with:

$ME= \frac{11.1248- 8.8104}{2}= 1.1572$

The margin of error for this case is given by:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE$

And we can solve for the standard error:

$SE = \frac{ME}{t_{\alpha/2}}$

The critical value for 95% confidence using the normal standard distribution is approximately 1.96 and replacing we got:

$SE = \frac{1.1572}{1.96}= 0.5904$

Now for the 98% confidence interval the significance is $\alpha=1-0.98= 0.02$ and $\alpha/2 = 0.01$ the critical value would be 2.326 and then the confidence interval would be:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

8 0

3 years ago