Answer:
Step-by-step explanation:
Steps to solve:
3x + 2 = 8
~Subtract 2 to both sides
3x = 6
~Divide 3 to both sides
x = 2
Best of Luck!
There is no difference, 6rs-(-2rs) if you get rid of the parenthesis you are left with 6rs- -2rs and two negatives make a positive therefore the answer will become 8rs... I hope this helps :)
Answer:
4x² -20x +61
Step-by-step explanation:
the quadratic equation can be written as (x-root1)(x-root2)
(x-(5/2) -3i) (x-(5/2)+3i), distribute
x² -(5/2)x +3xi -(5/2)x + 25/4 -(15/2)i -3xi +(15/2)i -9i², simplify
x² -(5/2)x -(5/2)x + 25/4 -9i², use the fact that i² =(√-1)² = -1 and substitute i²
x² -(5/2)x -(5/2)x + 25/4 +9, combine like terms and rewrite 9 as 36/4
x² -(10/2)x +25/4 + 36/4, combine like terms and simplify
x² -5x +61/4 is the quadratic expression yet it does not have integer coefficients so multiply by 4 to have all coefficients integers
4x² -20x +61
Given the equation - x² + 5x = 3, which can be rewritten as:
- x² + 5x - 3 = 0
where a = -1, b = 5 and c = -3.
Quadratic formula:
![\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2\text{ - 4ac}}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7Bb%5E2%5Ctext%7B%20-%204ac%7D%7D%7D%7B2a%7D)
Now, we just replace the values of a, b and c on the equation above.
![\frac{-5\text{ }\pm\text{ }\sqrt[]{5^2\text{ - 4(-1)(3)}}}{2(-1)}](https://tex.z-dn.net/?f=%5Cfrac%7B-5%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B5%5E2%5Ctext%7B%20-%204%28-1%29%283%29%7D%7D%7D%7B2%28-1%29%7D)
=
![\frac{5}{2}\text{ }\pm\text{ }\frac{\sqrt[]{13}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Cfrac%7B%5Csqrt%5B%5D%7B13%7D%7D%7B2%7D)
