Answer:
2/3
Step-by-step explanation:
4 subs 6 people
4/6= 0.66 repeated
so each person got 2/3 sub
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
The student's current average score will be 69.2
Step-by-step explanation:
Let first test be TEST A: which is 20 of total and secures 62
Let second test be TEST B: which is 20 of the total marks and has secured 83.
Let third test be TEST C: which is 20 of total and has secured 91.
And now the TEST D which is 25 of total and has secured 88.
Therefore, by multipying across
= 12.4
= 16.6
= 18.2
=22
Now, by adding the scores to get the average score
We get, 69.2.
Answer:
Ok im, not 100% sure but the answer is for 1-10, 2-20, 3-40, 4-40
