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3 years ago

Solve the equation 16y(2–y)+(4y–5)2=0

1 answer:

6 0

16y(2−y)+(4y−5)(2)=0

Step 1: Simplify both sides of the equation.

−16y2+40y−10=0

Step 2: Use quadratic formula with a=-16, b=40, c=-10.

y=−b±√b2−4ac2a

y=−(40)±√(40)2−4(−16)(−10)2(−16)

y=−40±√960−32

y=54+−14√15 or y=54+14√15

Answer:

y=54+−14√15 or y=54+14√15

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3 years ago

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4 years ago

Passing through point (4, 9) and perpendicular to the line y= -1/5x -3

Ratling [72]

Answer:

y = 5x-11

Step-by-step explanation:

The slope intercept form of a line is y =mx+b where m is the slope

y = -1/5 x-3

The slope is -1/5

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-1 * -5/1

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3 years ago

keisha spent 45 minutes at soccer practice on Monday and n minutes on Tuesday. Write an experession that repersents the number o

levacccp [35]

Answer:

45+n

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How to solve this problem?

valentinak56 [21]

Very nice handwriting but the math and English are confusing.

Let's assume we're told

$\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2$

The subscript is important.

I think we're told the similar sum with 11 gives the smallest possible value for the sum. This is a rather cagey way of telling us 11 is the mean of the nine points. The mean is the number which minimizes the sum of squared deviations.

$\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2 = \sum x_i^2 - 20 \sum x_i + 9(100)$

$\displaystyle \sum x_i^2= 20 \sum x_i - 900$

If 11 is the mean, the sum of the points is 9(11)=99.

$\displaystyle \sum x_i^2= 20 (99) - 900 = 1080$

Answer: 1080

6 0

4 years ago