3 years ago

Solve the equation 16y(2–y)+(4y–5)2=0

1 answer:

6 0

16y(2−y)+(4y−5)(2)=0

Step 1: Simplify both sides of the equation.

−16y2+40y−10=0

Step 2: Use quadratic formula with a=-16, b=40, c=-10.

y=−b±√b2−4ac2a

y=−(40)±√(40)2−4(−16)(−10)2(−16)

y=−40±√960−32

y=54+−14√15 or y=54+14√15

Answer:

y=54+−14√15 or y=54+14√15

You might be interested in

Determine the dimension of the vector space. M4,2

Fofino [41]

Answer:

STEP 1

M_{4,2} is set of 4x2 matrices hence each matrix has 4*2=8 entries. Each entry can be filled independently.

Hence its basis has 8 linearly independent vectors.

STEP 2

Dimension= cardinality of basis = 8.

6 0

3 years ago

HURRY I NEED HELP PLS

vampirchik [111]

Answer:

3,454 cm³

Step-by-step explanation:

This is a cylinder so the volume formula is $V=\pi r^{2} h$

The problem gives us the diameter (20 cm) and the height (11 cm). Since the formula uses the radius instead of the diameter, we have to divide the diameter by 2.

20 ÷ 2 = 10

The radius is 10 cm

Now, we plug our height and radius into the formula to find the volume.

$V=\pi r^{2} h\\V=(\frac{22}{7})(10)^{2}(11)\\V=(\frac{22}{7})(100)(11)\\$