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irga5000 [103]
3 years ago
6

Solve the equation 16y(2–y)+(4y–5)2=0

Mathematics
1 answer:
zmey [24]3 years ago
6 0
16y(2−y)+(4y−5)(2)=0

Step 1: Simplify both sides of the equation.

−16y2+40y−10=0

Step 2: Use quadratic formula with a=-16, b=40, c=-10.

y=−b±√b2−4ac2a

y=−(40)±√(40)2−4(−16)(−10)2(−16)

y=−40±√960−32

y=54+−14√15 or y=54+14√15

Answer:

y=54+−14√15 or y=54+14√15

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Answer:

  the correct choice is marked

Step-by-step explanation:

Let x represent the smaller number. Then the larger number is 8x, and the difference is ...

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The larger number is 8x = 8(40) = 320.

_____

<em>Additional comment</em>

Effectively, we have solved for the multiplier (40) that gives the ratio with 320 on top and a difference between top and bottom of 280:

  \dfrac{8}{1}=\dfrac{8\cdot40}{1\cdot40}=\dfrac{320}{40}

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