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Nezavi [6.7K]
3 years ago
14

Erin records the following temperatures (in degrees

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

I think the correct answer should be B

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Can someone answer this question for me pls n thanks
allsm [11]

Answer:

Mean: 29.5;    Median: 26;    Modes: 25, 26

Step-by-step explanation:

Add 10+12+25+25+26+26+30+31+33+34+47+55 = 354

Then divide it by 12      354/12 = 29.5

Mode are numbers that appear most often which in this case are 2 numbers, 25 and 26.

8 0
2 years ago
A rectangular poster is to contain 722 square inches of print. the margins at the top and bottom of the poster are to be 2 inche
Delvig [45]
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need to minimize the area A=x*y

we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2

so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4

find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]

for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in

(y)=[722/(x-4)]+2

y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in

the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in

6 0
3 years ago
The number 900 is increased by 20% and then decreased by 20%. Find the new number.(the ans is 864 apparently:/ I need steps)
Georgia [21]

Step-by-step explanation:

if 900 is increased by 20% then

120/100×900=1080

Decreasing it by 20% then

80/100×1080=864

5 0
2 years ago
Did you hear about the two punsters who told a lot of jokes about cats
Serggg [28]
Ooo. I I didn't hear please do tell
4 0
3 years ago
What is the radius of the circle given by the equation (x-2)^2+y^2=14
Rainbow [258]
The general equation of a circle is
 (x-a) ^ 2 + (y-b) ^ 2 = r ^ 2
 for this case the values of a and b are
 a = 2
 b = 0
 The radius of the circle is
 r ^ 2 = 14
 r = (14) ^ (1/2) = 3.74

8 0
3 years ago
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