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Galina-37 [17]
3 years ago
6

6. Find the missing length. Round the the nearest tenth

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

6. 10 7.100

Step-by-step explanation:

that is the answer

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Ken predicts that the average temperature will be −5°C in December. If he predicts the temperature will rise 6°C in January and
ipn [44]

Answer:

The equations [(-5) + (-3)] + 6 = -2 and [6 + (-5)] + (-3) = -2  he can use to find the sum of the temperatures for those months ⇒ 3rd , 5th

Step-by-step explanation:

i took the assignment

7 0
3 years ago
9Find -18 + (-67). Show your work.
polet [3.4K]

Answer:

-85

Explanation:

Given the mathematical expression:

-18+(-67)

First, we recall the product of signs.

+\times-=-

So, first, we open the bracket:

-18+(-67)=-18-67

We then simplify:

=-85

The result is -85.

3 0
1 year ago
What does "As Much" mean in math? I am doing homework and I don't want to fail so I really need help.
igor_vitrenko [27]
It means the same used in a question like this, is 25 as much as 25.
4 0
3 years ago
Can someone plz help?
vagabundo [1.1K]

your answer is C. substraction

4 0
3 years ago
n automatic machine in a manufacturing process is operating properly if the lengths of an important subcomponent are normally di
Paraphin [41]

Answer:

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.

This means that \mu = 116, \sigma = 5.4

Find the probability that one selected subcomponent is longer than 118 cm.

This is 1 subtracted by the pvalue of Z when X = 118. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{118 - 116}{5.4}

Z = 0.37

Z = 0.37 has a pvalue of 0.6443

1 - 0.6443 = 0.3557

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

8 0
3 years ago
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