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musickatia [10]
3 years ago
12

Can someone help me please?

Mathematics
2 answers:
Leno4ka [110]3 years ago
5 0

Answer: Hi

Step-by-step explanation:

The answer is b

TEA [102]3 years ago
4 0
B and c if it’s an optional question
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Whats the GCF of 49 and 4
Irina18 [472]
The greatest common factor is 1 because there is not a number that goes into or will multiply and get 49 and 4. 49 is an odd number and 4 is an even number so the GCF is 1.
5 0
3 years ago
PLEASE ANSWER QUICKLY: SURFACE AREA<br><br> If you don't know the answer please don't guess.
dusya [7]
Well for one, the floor and the ceiling do not need wallpaper.  So you would only find the surface area each side.  (48, 48, 80, 80)  Then you would add all four together. (256ft squared)

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3 0
3 years ago
Solve for x in the equation x squared + 14 x + 17 = negative 96. x = negative 7 plus-or-minus 4 StartRoot 6 EndRoot i x = –7 ± 8
blagie [28]

Answer:

x=-7\pm8i

Step-by-step explanation:

we have

x^{2} +14x+17=-96

Equate to zero

x^{2} +14x+17+96=0

x^{2} +14x+113=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} +14x+113=0

so

a=1\\b=14\\c=113

substitute in the formula

x=\frac{-14\pm\sqrt{14^{2}-4(1)(113)}} {2(1)}

x=\frac{-14\pm\sqrt{-256}} {2}

Remember that

i=\sqrt{-1}

so

x=\frac{-14\pm16i} {2}

x=-7\pm8i

7 0
3 years ago
Read 2 more answers
The following temperatures were recorded in Pasadena for a week in April: 87, 85, 80, 78, 83, 86, 90. Determine the interquartil
Lubov Fominskaja [6]

Answer:

7

Step-by-step explanation:

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7 0
3 years ago
Pls help, I've been stuck on this for a week
crimeas [40]

Answer:

\sin(C)=\pm\sqrt{1-\cos^2(C)}

Step-by-step explanation:

Given the Pythagorean Identity:

\sin^2(C)+\cos^2(C)=1\\

We want to solve for sin(C).

First, we will subtract cos²(C) from both sides:

\sin^2(C)=1-\cos^2(C)

Next, we will take the square root of both sides. Since we are taking an even-root, we will need to add plus/minus. Hence:

\sin(C)=\pm\sqrt{1-\cos^2(C)}

5 0
3 years ago
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