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Crazy boy [7]
3 years ago
11

This is due in a bit and im having a bit of trouble, any solutions?

Mathematics
1 answer:
valina [46]3 years ago
5 0

Answer:

I believe that those triangles are not similar

Step-by-step explanation:

5 is 1.666 of 3

20/3=6.667

1.666 does not equal 6.667

if I did that correctly, they are not similar

Hope this helps!

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X2 − 2x − 2 into the form a(x − h)2 + k.
Sedbober [7]

Answer:

x² - 2x - 2

By Completing the Square....

x² - 2x + 1² - 2 - 1²

(x - 1)² - 3 .....

Hope it helps.

3 0
2 years ago
Which of the following show an element of the sample space for first rolling a die and then tossing a coin?
Sphinxa [80]
A because if you use T3 it wouldn’t have make sense so only reasonable and solution that works is A
5 0
2 years ago
Find the first five terms that correspond with the following expression.<br><br> 4n + 2
Lorico [155]

Answer:

6,10,14,18,22

Step-by-step explanation:

4n+2

Let n=1  4(1)+2 = 4+2 = 6

Let n=2  4(2)+2 = 8+2 = 10

Let n=3  4(3)+2 = 12+2 = 14

Let n=4  4(4)+2 = 16+2 = 18

Let n=5  4(5)+2 = 20+2 = 22

7 0
2 years ago
Dianna made several loaves of bread yesterday. Each loaf required 2 cups of flour. All together, she used 135 cups of flour. How
irinina [24]

Answer:

The answer is not in the options, it is 67.5

Step-by-step explanation:

135/2 = 67.5

4 0
3 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
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