This is due in a bit and im having a bit of trouble, any solutions?
1 answer:
You might be interested in
<h2>Greetings!</h2>
<h2>Hope this helps!</h2>
Answer:
One number is and the other number is
Step-by-step explanation:
Let x be the smaller number and y be the bigger number.
x = x
y = 5x
6x + 3y = 3
6x + (3 * 5x) = 3
6x + 15x = 3
(÷3)
2x + 5x = 1
7x = 1
x =
6x + 3y = 3
6() + 3y = 3
+ 3y = 3
3y = 3 -
3y =
Divide both sides by 3 to get 1y:
y =
So one number is and the other number is
<h2>Hope this helps!</h2>
Answer:
1.2%
Step-by-step explanation:
We are given that the students receive different versions of the math namely A, B, C and D.
So, the probability that a student receives version A = .
Thus, the probability that the student does not receive version A = =
.
So, the possibilities that at-least 3 out of 5 students receive version A are,
1) 3 receives version A and 2 does not receive version A
2) 4 receives version A and 1 does not receive version A
3) All 5 students receive version A
Then the probability that at-least 3 out of 5 students receive version A is given by,
+
+
=
=
=
=
= 0.01171875 × 1.0625
= 0.01245
Thus, the probability that at least 3 out of 5 students receive version A is 0.0124
So, in percent the probability is 0.0124 × 100 = 1.24%
To the nearest tenth, the required probability is 1.2%.