Answer:
C
Step-by-step explanation:
Answer:
Let x be odd such that LCM {x,40} = 1400 .
Since 1400 = 23×52×7 , then
x ∈ {5m×7n∣(m,n) ∈ {0,1,2}×{0,1}} .
By testing these values, we find that x = 175 .
8-5=3 is the remaining half
weekly allowance=2(1÷2) where (1÷2) is 3
2×3=6
The weekly allowance should be 6.
Answer:
1
0
(
3
+
4
)
Step-by-step explanation:
