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3 years ago

Rectangle JKLM is shown.

Mathematics

1 answer:

ad-work [718]3 years ago

6 0

Answer:

Step-by-step explanation:

We can use the Pythagorean theorem to solve this.

(13)^2 = (8)^2+x^2

169 = 64 + x^2

x^2 = 105

x is approximately 10.2, so B

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Scientists are creating a material that may replace damaged cartilage in human joints. This hydrogel can stretch to 21 times its

Oduvanchick [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Let B be the basis of P3 consisting of the Hermite polynomials in Exercise 21, and let p.t / D 7 ! 12t ! 8t 2 C 12t 3. Find the

Anastasy [175]

To calculate the relative vector of B we have to:

$P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]$

The coordenates of:

$p(t)= 12t^3-8t^2-12t+7$ , with respect to B satisfy:

$C_1(1)+C_2(2t)+C_3(-2+4t^2)+C_4(-12t+8t^3)= 7-12t-8t^2+12t^3$

Equating coefficients of like powers of t produces the system of equation:

$\left \{ {C_1-2C_3=7} \atop {2C_2-12C_4=-12} \right. \\\left \{ {{4C_3=-8} \atop {8C_4=12}} \right.$

After solving this system, we have to:

$C_1=3\\C_2= 3\\C_3= -2\\C_4= \frac{3}{2}$

And the result is:

$P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]$

Learn more: brainly.com/question/16850761

4 0

3 years ago

Solve x^2 − 4x = 14.

DENIUS [597]

Minus 14 from both sides
x²-4x-14=0
use quadratic formula because we cant factor

for
ax²+bx+c=0
$x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$

so
1x²-4x-14=0
a=1
b=-4
c=-14

$x= \frac{-(-4)+/- \sqrt{(-4)^2-4(1)(-14)} }{2(1)}$
$x= \frac{4+/- \sqrt{16+56} }{2}$
$x= \frac{4+/- \sqrt{72} }{2}$
$x= \frac{4+/- 6\sqrt{2} }{2}$
$x= 2+/- 3\sqrt{2}$

the solutions are
x=2+√3 and
x=2-√3

3 0

3 years ago

Which graph represents the function f(x) = -x ^2+ 5?<br> -10 - -<br> 60

blagie [28]

Answer:

Step-by-step explanation:

4 0

2 years ago

The difference between the roots of the quadratic equation x^2−12x+q=0 is 2. Find q.

shtirl [24]

Answer:

The required value of q is 35.

Step-by-step explanation:

Let α and β are the zeros of quadratic equation, x^2−12x+q=0.

It is given that difference between the roots of the quadratic equation x^2−12x+q=0 is 2.

Equation : α - β = 2

Equation : α + β = 12

Equation : αβ = q

We have to create an algebraic expression.

(a+b)² = (a-b)² + 4ab

(12)² = (2)² + 4q

144 = 4 + 4q

144 - 4 =4q

140=4q

q = 140/4

q = 35

Therefore, the required value of q is 35.

<u>Some information about zeroes of quadratic equation. </u>

Sum of zeroes = -b/a
Product of Zeroes = c/a

5 0

3 years ago