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RUDIKE [14]
3 years ago
11

Help me pleaseeeeeeeeeeeeee

Mathematics
1 answer:
ser-zykov [4K]3 years ago
5 0

Answer:

dfhjkbfgv u u u ucuvvcuvuvuc y y y y y y y y y h u h h u u h h h h uu uu u u uu

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which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l
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One equation for this would be

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m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}&#10;\\&#10;\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})&#10;\\&#10;\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})&#10;\\&#10;\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}

A line parallel to this one will have the same slope.  We will use point-slope form to write our equation:

y-y_1=m(x-x_1)&#10;\\&#10;\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})&#10;\\&#10;\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}&#10;\\&#10;\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}&#10;\\&#10;\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{550}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{55}{8}
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Answer:

0; one real roots

* the answer is C

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