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Mekhanik [1.2K]
2 years ago
15

Can someone plz help me ?

Mathematics
1 answer:
nevsk [136]2 years ago
4 0

Answer: x= -1, 0, 1      y= -5, -3, -1

Step-by-step explanation:

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Can someone help with the two triangle questions (will mark brainliest!!)
yaroslaw [1]

Answer: Number 1 is c=89 ft

Number 2 is b=3 cm

Step-by-step explanation: a²+b²=c²

For number 1, 39 ft is a and 80 ft is b so

39²+80²=c² so 39² is 39x39=1521 and 80² is 80x80=6400 so 6400+1521=7921

7921=c² and the square root of 7921 is 89 so c=89 ft

For number 2, a=1.6 cm and c=3.4 cm so 3.4²-1.6²=b²

3.4² so 3.4x3.4 which is 11.56

1.6² so 1.6x1.6 which is 2.56

11.56-2.56=c² and 11.56-2.56=9

Square root of 9 is 3 so b=3

So number 2 answer is b=3 cm

I hope this helps

4 0
2 years ago
GEOMETRY-TRIG
Andrej [43]

Answer:

6. The distance Rampy Ronald would have travelled horizontally is approximately 48.428 feet for an actual maximum height of 21.486 feet

7. Rampy Ronald is going to make the jump

Please find attached the graph of the motion of Rampy Ronald, created with Microsoft Excel

Step-by-step explanation:

6. The given parameters are;

The width of the ravine = 80 ft

The inclination of the ramp with which Rampy Ronald will jump = 30°

The distance from the edge of the ravine the ramp ends = 5 feet

The speed with which Rampy Ronald will make the jump = 60 mph

The maximum height he will reach = 30 feet

Therefore, we have;

The height of the end of the ramp = 15 × sin(30°) = 7.5

The height of the end of the ramp = 7.5 feet

The height of the jump = 30 - 7.5 = 22.5

The vertical velocity = 60 × sin(30°) = 30

The vertical velocity = 30 mph

The horizontal velocity = 60 × cos(30°) = 30·√3

The horizontal velocity = 30·√3 mph

From the kinematic equation, v² = u² - 2gh, we have;

u² = 2gh

h = u²/2g = 900/(2 × 32.17405) ≈ 13.986

The maximum height reached 13.986 + 7.5 = 21.486

From v = u - gt

t = u/g = 30/32.17405 ≈ 0.932

t  ≈ 0.932 s

The distance Rampy Ronald would have travelled horizontally = 30·√3 × 0.932 ≈ 48.428

The distance Rampy Ronald would have travelled horizontally ≈ 48.428 feet

7. The time before Rampy Ronald reaches ground level again, is given by the following relation;

h = 1/2·g·t²

21.846 = 1/2 × 32.17405 × t²

t = √(21.846/16.087025) ≈ 1.165

t ≈ 1.366 s

The horizontal distance traveled is therefore;

The horizontal distance traveled from maximum height is 30·√3 × 1.165 ≈ 60.535

The horizontal distance traveled from maximum height is ≈ 70.979 feet

The total horizontal distance traveled ≈ 48.428 + 60.535 = 108.963

The total horizontal distance traveled ≈ 108.963 feet

The total horizontal distance required to make it across the ravine = 5 feet + 80 feet = 85 feet

Therefore, Rampy Ronald is going to make the jump

8 0
2 years ago
If m1=35° and m2=75°, what is m3?​
Sveta_85 [38]

Answer:

m3 should be 70°

all internal angles of a triangle add up to 180

180-35-75 = 70

4 0
3 years ago
Read 2 more answers
Please simplify this expression ! Show your work and please answer this !!
tangare [24]

Answer:

18q^2 - 52q + 32

Step-by-step explanation:

We can use the Distributive Property to solve this.

(2q-4)(9q-8)

2q(9q) + 2q(-8) + -4(9q) + -4(-8)

18q^2 - 16q - 36q + 32

18q^2 - 52q + 32

18q^2 - 52q + 32

6 0
3 years ago
g(x)=2x+9g, left parenthesis, x, right parenthesis, equals, 2, x, plus, 9 g ( g(g, left parenthesis ) = 15 )=15right parenthesis
Dmitriy789 [7]

Answer:

I don't understand your question

6 0
3 years ago
Read 2 more answers
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